K(eq)= 1.33
N2 + 3H2 -------> 2NH3
No, it's not balanced because the number of hydrogens and nitrogens on the left is not equal to the number on the right. 3H2 + N2 --> 2NH3
Mn is for manganese I think. Ok first of all check the number of molecules on each side. on the left, Mn has 1, Oxygen has 2, Nitrogen has 1, Hydrogen has 4. On the right hand, Mn has 2,Oxygen has 3, nitrogen has 1 and Hydrogen has 5. all need to be balanced.So the resulting coefficients on both sides should be;2(MnO2) + 2(NH4) --- > Mn2O3 + 2(NH3) + H2O
First make the reaction equation balanced for N-atoms (co-existant in both formula)N2O5 + H2O --> 2 HNO3So 1.02 mole HNO3 is produced from:1.02 x 1 (N per HNO3) / 2 (N per N2O5) = 0.51 mol N2O5
Most drain cleaners use a simple formula of lye (concentrated sodium hydroxide) in order to disrupt whatever is clogging the drain. Other strong bases like potassium hydroxide may also be used.
keq = 1.125
keq = 1.125
2NH3 is the product of N2+3H2
The balanced equation for this reaction is: N2(g) + 3H2(g) → 2NH3(g).
The balanced equation for this reaction is: 3H2 + N2 -> 2NH3
To calculate the equilibrium constant ( K_{eq} ) for the reaction ( N_2 + 3H_2 \rightleftharpoons 2NH_3 ), you would need the equilibrium concentrations of the reactants and products. The formula for ( K_{eq} ) is given by ( K_{eq} = \frac{[NH_3]^2}{[N_2][H_2]^3} ). Once you have the equilibrium concentrations of ( NH_3 ), ( N_2 ), and ( H_2 ), you can substitute those values into the formula to find ( K_{eq} ). Without specific concentration values, the exact numerical result cannot be provided.
N2 + 3H2 <--> 2NH3 Born-Haber process and an equilibrium reaction. So, pressure and temperature must be maintained to keep the reaction going in the products direction. Google Born-Haber reaction.
This is the balanced chemical equation for the Haber process, which produces ammonia. To solve, you can balance the equation by adjusting the coefficients in front of each compound to ensure that the number of each type of atom is the same on both sides of the equation. In this case, the balanced equation is N2 + 3H2 -> 2NH3.
3H2 + N2 --> 2NH3 Since Hydrogen (H) and Nitrogen (N) both appear in nature diatomically they only appear as H2 and N2. We must add 3 molecules of Hydrogen and 1 molecule of Nitrogen to get 2 molecules of ammonia. We cannot, in nature, have half of a diatomic Hydrogen or Nitrogen atom, for that reason the equation must yield 2 molecules of Ammonia.
Also called haber's process to manufacture Ammonia- N2 + 3H2---> 2NH3 + 22400 Kcal energy
The balanced symbol equation for the formation of ammonia is: N2 + 3H2 → 2NH3
There weren't any answer choices provided. But I found an example and if this is the example N2(g) plus 3H2(g) equals 2NH3(g) then the answer is none of the above. The question is messed up and all of the answer choices are the same.