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What is the Kinetic Energy of the trolley at the top of the ramp if a trolley of mass is 25Kg and is released from the top of a ramp which stands at a height of 3m?
Wiki User
∙ 14y ago
What is the Kinetic Energy of the trolley at the top of the ramp if a trolley of mass is 25Kg and is released from the top of a ramp which stands at a height of 3m?
Mass = 25 Kg
Height = 3 m
This is an energy problem. At the top of the ramp, the trolley is at rest and 3m above the base line.
Potential Energy = Weight * height
Weight = mass * acceleration due to gravity
Acceleration due to gravity = 9.8m/s^2
Potential Energy = 25 kg * 9.8m/s^2 * 3 m
Potential Energy = 735 Joules
When the trolley reaches the bottom of the ramp, all the potential energy has been converted to Kinetic energy.
Potential Energy = 735 Joules = Kinetic energy
Kinetic energy = ½ * mass * velocity^2
Kinetic energy = ½ * 25 * V^2 = 735 multiply 735 by 2 and divide by 25
V^2 = 58.8
V = 7.67 m/s
Wiki User
∙ 14y ago
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