What is the Lewis dot structure for SiF62?

Answer 1

Silicon has 4 valence electrons Fluorine has 7 electons each. SiF4 has 4 single bonds. Silicon contributes one electron to each bond and fluorine contributes one electron. Each fluorine has three lone pairs of electrons left over. If I could paste a picture I would but this is the best I could do for a illustration

..

: F :

.. .. ..

: F : Si : F :

.. .. ..

: F :

..

its shape is tetrahedral with 109.5 degrees apart

Answer 2

Si is the central atom, surrounded by four Cl atoms through single bonds. There are no lone pairs around the Si atom, and each Cl atom holds three lone pairs.

Electron Domain Geometry: Tetrahedral

Molecular Geometry: Tetrahedral

Answer 3

SeF4 I couldn't properly draw it with the available tools, so I hope you understand! I put two PAIRS of electrons on the middle F atoms, because I didn't have the tools but they should be technicaly below it!!!! Valency of Se: 6 and F: 7. Hence 6+4(7) = 34e- MIND: There are also two extra electrons on Se!!! .. .. :F: :F:

.. \ / ..

::F - Se - :F::

/ \

:F: :F:

.. ..

Answer 4

Si has 4 valence electronsH has 1 valence electron each so a total of 2

F has 7 valence electrons each so a total of 14

Put Si in the middle (least electronegative) and put 2 H atoms and 2 F atoms attached to the Si. Then put 3 lone pairs (6 electrons) around each of the two F atoms. That is the Lewis dot structure.

Answer 5

The dot structure for silicon tetraflouride starts with the Si atom in the middle. On each cardinal side is a singly bonded F atom, each with six dots.

Answer 6

___H ___

___! ___

H- Si - H

___! ___

___H___

0 because the outer shell of Si has 4 electrons which are all taken up with the bonding with the 4 Hs