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According to Nyquist Signaling Theorem:

Rmax = 2Wc pulse/second


where R is the maximum transmission rate in pulse/second

Wc is the channel bandwidth

In your case you have R in bit/s, so the theorem becomes


Rmax = 2Wc *m bit/second


where m is the number bits in each pulse, i.e. bit/pulse


So the solution to your problem is


Wc=9600/(2*4)=1200 Hz


Regards,


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Q: What is the Minimum required channel bandwidth of a 4 bit word operating at 9600 bps?
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