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What is the Molarity of a substance that contains 4.13 grams of magnesium bromide in 845 liters of a solution?
Wiki User
∙ 14y ago
Molarity= mols/ L
So, take 4.13g MgBr2 ( because Mg has a +2 charge and Bromide has a +1 charge) and divide it by 184.1 g MgBr2 which gives you .022 mols of MgBr2 then you divide .022 by 845 which gives you 2.65 M
Molarity = 2.65M
Wiki User
∙ 14y ago
To find the molarity of the substance, divide the moles of the substance by the volume of the solution in liters. First, calculate the moles of magnesium bromide:
- Convert grams to moles by dividing the given mass by the molar mass of magnesium bromide (184.1 g/mol).
- Moles of magnesium bromide = 4.13 g / 184.1 g/mol = 0.0224 mol.
Next, divide the moles by the volume of the solution in liters:
- Molarity = 0.0224 mol / 845 L ≈ 0.00003 M (rounded to 3 significant figures).
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