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It is related to concentration, which you do not give.

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Geoffrey Huels

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2y ago
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8y ago

H2SO4 is a strong acid for the first dissociation where H2SO4 ---> H+ + HSO4-

Neglecting the second dissociation which is small compared to the first, the [H+] = 0.3 M

pH = -log [H+] = -log 0.3

pH = 0.5

NOTE: if you want to include the second dissociation, you need to look up the Ka for that, calculate the [H+] from that dissociation, add it to the 0.3 M and then find negative log of that value.

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14y ago

It is related to concentration, which you do not give.

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Q: What is the Ph value for 0.005N H2SO4?
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