Assuming pH on just simple concentration.
- log(0.01 M H2SO4)
= 2 pH
=====
The answer is 0,526 mL.
The answer is 7,66 L.
The answer is 293,64 mL.
how will make solution for 0.005 h2so4
100% pure H2SO4 doesn't exist
Molarity = moles of solute/volume of solution ( so, not a great molarity expected ) 4.60 grams H2SO4 (1mol H2SO4/98.086g) = 0.0469 moles/450ml = 1.04 X 10^-4 Molarity.
The answer is 0,526 mL.
The answer is 7,66 L.
The answer is 293,64 mL.
how will make solution for 0.005 h2so4
100% pure H2SO4 doesn't exist
For a detailed answer visit: algebra.com/algebra/homework/word/mixtures/Mixture_Word_Problems.faq.question.786696.html
The answer is 1,2 mol.
Sulphuric Acid requires, I believe 27.2ml to make a 1N solution.
The first solution is more concentrated because it contains 6 moles of H2SO4 per one liter of solution. The second solution is less concentrated because it contains 0.1 moles of H2SO4 in one liter. In equal amounts of each example, the first would have more H2SO4.
You need 49,8 mL H2SO4 6,4M.
h2so4 can reduce fehling solution