The String class includes two helpful methods: equals and compareTo.
string1.equals(string2) will return true if the two strings contain the exact same characters
string1.compareTo(string2) will return an int which describes the lexicographic relationship between the two strings. It will return a negative value if string1 is "less than" string2, a positive value if string1 is "greater than" string2, or zero if the two are equivalent strings.
Strings in java cannot be compared using the OR operator. The OR is a logical operator which can do only a ture or false check and not the values contained in a String.
Compare the first two numbers with the ternary operator. Store the result in a temporary variable. Compare the temporary variable with the third number, again using the ternary operator.
pancakes
Yes, the if the two string objects point to the same memory location. But "==" is not the best way to compare two string objects. Two strings can be compared using obj1.equals(obj2). This compares for the textual equal-ness of the two string objects.
I will not use operator overloading in C# to do anything. Operator overloading may lead to one operator has more than 1 semantic meaning. For example, we know 1 + 2 yields 3, and "1" + 2 yields "12". I do not like this overloading of the operator + being used for addition in Number hierarchy, while as the concatenation in strings. That is, one operator (+) has 2 significant semantics.And the question "find largest of two object" is too vague - what do you mean "largest"? and object? We know apple and orange are 2 objects, but how do you compare them, and find the largest one?????? (size, price or what???)
You cannot compare 2 numbers without using relational operators. Certainly, you could subtract them, but you still need to test the result, and that is a relational operator in itself.
System.out.println(a.equals(b) ? "They are equal" : "They are different");System.out.println(a.equals(b) ? "They are equal" : "They are different");System.out.println(a.equals(b) ? "They are equal" : "They are different");System.out.println(a.equals(b) ? "They are equal" : "They are different");
Compare the first two numbers with the ternary operator. Store the result in a temporary variable. Compare the temporary variable with the third number, again using the ternary operator.
Program below?!
nahi malum
write a c program to fine largest/smallest of 3no (using ?:ternary operator/conditional operator)
pancakes
Yes, the if the two string objects point to the same memory location. But "==" is not the best way to compare two string objects. Two strings can be compared using obj1.equals(obj2). This compares for the textual equal-ness of the two string objects.
how to compare two strings that take input from the user and compare it. For example: i give first string as "THE" and give second string as "HTE" then return "match" if i give first as"THE" nd second string as "EHI" then return "NOtMatch" witout using STRCMP ... please help me
somecommand > historywhere somecommand is the program that normally prints to stdout. The redirection operator is the > symbol.
char one [] = "A string" ;char two [] = "Different String" ;if (strcmp (one, two) == 0){puts ("The two strings are identical") ;}else{puts ("The two strings are different") ;}
I will not use operator overloading in C# to do anything. Operator overloading may lead to one operator has more than 1 semantic meaning. For example, we know 1 + 2 yields 3, and "1" + 2 yields "12". I do not like this overloading of the operator + being used for addition in Number hierarchy, while as the concatenation in strings. That is, one operator (+) has 2 significant semantics.And the question "find largest of two object" is too vague - what do you mean "largest"? and object? We know apple and orange are 2 objects, but how do you compare them, and find the largest one?????? (size, price or what???)
You cannot compare 2 numbers without using relational operators. Certainly, you could subtract them, but you still need to test the result, and that is a relational operator in itself.