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Q: What is the R Card and C Card for a T1?
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What is the equation for temperature coefficient of resistance?

R= R0 * [1 + rho( t2-t1 ) ] so from this equation , rho= R-R0/[R0(t2-t1)] where rho- coefficient of resisivity R-resistance at any time t R0- resistance at 00C t2-final temperature t1-initial temperature


How many kg of ice need to be added to 1.93kg of water at 59.4 degrees celsius to cool the water to 13.4 degrees celsius?

Q=mcT T1 = (59.4-13.4)°C = 46°C (water)->46 K m1 = 1.93 kg c = 4180 J/(kg x K) T2 = (13.4-0)°C = 13.4°C (ice)->13.4 K m2 = ? Q1=Q2 m1 c T1=m2 c T2 m2= (m1 c T1) / (c T2) = (m1 T1) / T2 = 6.63 kg


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How can you get wireless through your T1?

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Find the common ratio of the following geometric sequence 2.512 11.304 50.868 228.906 1030.077?

Formula for the nth term of general geometric sequence tn = t1 x r(n - 1) For n = 2, we have: t2 = t1 x r(2 - 1) t2 = t1r substitute 11.304 for t2, and 2.512 for t1 into the formula; 11.304 = 2.512r r = 4.5 Check:


Line side T1 what is its purpose?

The purpose of a line-side T1 is to directly connect two devices, using a T1, without going through a service provider. This is done in lieu of using analog circuits or if IP connectivity/trunking is not available. For example, a fax server can connect directly to a corporate PBX, via a line side T1, using a cross-over 2-pair, 22 AWG shielded twisted pair cable. This is a direct connection from the PBX's T1 card to the fax server's T1 card. Provisioning of the T1 circuit is done in both the PBX and the fax server to accommodate the medium (24 channels, robbed-bit signaling).


What is the first term of the Geometric series with a sum of 1022 the last term is 512 and the common ratio is 2?

The sum of the first n terms of a geometric series isSn = [t1(1 - r^n)]/(1 - r) (1)where r is the common ratio and t1 is the first term.The last term is tn = (t1)[r^(n - 1)] (2).We know the sum and the common ratio, but we don't know how many terms are in this series. So, in order to find the first term t1 we need to find n.From formula (1):Sn = [t1(1 - r^n)]/(1 - r)Sn(1 - r) = t1(1 - r^n)t1 = [Sn(1 - r)]/(1 - r^n)From formula (2):tn = (t1)[r^(n - 1)]t1 = tn/[r^(n - 1)] (3)So we have:[Sn(1 - r)]/(1 - r^n) = tn/[r^(n - 1)] substitute Sn = 1.022, r = 2, and tn = 512;[1,022(1 - 2)]/(1 - 2^n) = 512/[2^(n - 1)]-1,022/(1 - 2^n) = 512/[(2^n/2^1)]-1,022/(1 - 2^n) = 512(2/2^n) divide by 2 to both sides;-511/(1 - 2^n) = 512/2^n cross multiply;(-511)(2^n) = (512)(1 - 2^n)(-511)(2^n) = 512 - (512)(2^n) add (512)(2^n) to both sides;2^n = 512 rewrite this in its logarithmic form;n = log(base 2) of 512n = log 512/log 2n = 9From formula (3):t1 = tn/[r^(n - 1)] substitute tn = 512, r = 2, and n = 9;t1 = 512/[2^(9 - 1)]t1 = 512/2^8t1 = 512/256t1 = 2Thus the first term is 2.Check:1,022 = [2(1 - 2^9)]/(1 - 2) ?1,022 = [2(1 - 512)]/(-1) ?1,022 = ((2)(-511)]/(-1) ?1,022 = -1,022/-1 ?1,022 = 1,022 True


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How do you calculate half-life?

Check the time between your first decay rate and when the decay rate reaches half this number. Half life T1/2 is calculated using the below formula T1/2=0.6931/r Where r is disintegration constant