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4200 joules = 1000 calories = kilocalorie
All types of energy are measured in joules. Heat is a type of energy.
The mechanical equivalent of heat is 4.2 Joules/calorie, so 60.1 calories = 252.42 Joules
No, Fahrenheit is the Imperial Unit for temperature, not heat. Heat is energy in transit and is measured in joules (in the SI sytem).
Therm is a unit of heat equivalent to 100,000 British thermal units or 1.055 x 10^8 joules. The therm is often used by the engineers in the United States.
A Joule is the SI unit of energy. It is equal to 1 Newton force, multiplied by 1 meter.The calorie is a heat energy unit. Equal to approx 4.184 Joules. In food Calories, is actually equivalent to a kilocalorie (1000 calories, or 4184 Joules).
Standard units of heat is Joules.
Joules(J).
calories or joules
4200 joules = 1000 calories = kilocalorie
it is in joules. 03o
it is in joules. 03o
The unit for specific heat is Joules/g-Kelvin or it can be Joules/g-Celsius J= Joules g= Grams C= Celsius
BTU's or calories are directly related to the heat capacity of a substance or the heat produced in a reaction. All energy can be expressed in Joules, and for heat the relation is 4.2 Joules per calorie, this is called the mechanical equivalent of heat.Thermal energy is measured in joules (j).1 calorie = 4.2 JoulesAnswerIn SI, all forms of energy are expressed in joules(J).The British Thermal Unit (BTU) is an imperial unit for energy, rarely used anywhere outside the United States. The calorie is an obsolete (cgsA) unit despite being used (kilocalories) to some extent in the food industry.The terms, 'heat energy' and 'heat capacity' are both obsolete, having been replaced with 'internal energy' and 'specific heat capacity' (which is expressed in joules per kilogram kelvin).Work and heat are both described as energy in transit, and measured in joules.
measured in Calories, Btu, Joules, ...
Specific heat is the heat required to raise the temperature of a unit mass by one degree. It is measured by joules.
Joule/kilogram-kelvin The SI unit is joules / kelvin. This is valid for an object of any size, but if you want the typical specific heat for a certain type of material, you have to standardize it, resulting in either joules / (kelvin x kilogram) or joules / (kelvin x mole).