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5
4 N upward
15N
The buoyant force is the weight of the displaced water. That's 15n, and it points upward. That upward force combines with the downward 20n due to gravity. The net force on the object is 5n downward.
T = R x F T = 0.5m x 15N T = 7.5 N*m
put your hand there to stop it.
5
4 N upward
kiss my butt
15N
The buoyant force is the weight of the displaced water. That's 15n, and it points upward. That upward force combines with the downward 20n due to gravity. The net force on the object is 5n downward.
T = R x F T = 0.5m x 15N T = 7.5 N*m
The first thing to do is define a positive direction. The right is often defined as being positive, so we shall use that in this problem. We can now define the forces. Let F1= 100lb and F2 = -30lb (It is negative because it is pointing to the left.) Now simply add up the forces: Fnet = F1+F2 Fnet = 100lb + (-30lb) Fnet = 70lb
The box will accelerate to the left as though a single 5 N force was pushing to the left. (5 N of each force are cancelled out, leaving 5 N of the force pushing left.)
-5 -15n = 10add 5 to both sides-15n = 15divide both sides by -15n = -1
torque = force * lever length torque = 15 * 55 torque = 825 n-cms
14