2x plus 7z equals 64 8y plus 6z equals 40 3x-2y plus 4z equals 46?
Solve by the substitution method the given system of the linear equations of 3 variables.2x + 7z = 648y + 6z = 403x - 2y + 4z = 46 (add the first equation with the second equation)2x + 8y + 13z = 1043x - 2y + 4z = 46 (multiply the second equation by 4)2x + 8y + 13z = 10412x - 8y + 16z = 184 (add both equations)14x + 29z = 28814x + 29z = 2882x + 7z = 64 (multiply the second equation by -7)14x + 29z = 288-14x - 49z = -448 (add both equations)-20z = -160 (divide both sides by -20)z = 82x + 7z = 64 (substitute 8 for z)2x + 7(8) = 642x + 56 = 64 (subtract 56 to both sides)2x = 8(divide by 2 to both sides)x = 48y + 6z = 40 (substitute 8 for z)8y + 6(8) = 408y + 48 = 40 (subtract 48 to both sides)8y = -8 (divide by 8 to both sides)y= -1Thus, the solutions are x = 4, y = -1, and z = 8.