The voltage drop in any branch (closed loop) of a series parallel circuit is equal to the APPLIED VOLTAGE(NOVANET)
Without looking in my codebook, I believe it is 2% on a branch circuit.
under internal fault conditions , CT primary current produces steep insrease in voltage across the relay. This will exceed the burden 3kv normally designed as per. To get protected from the voltage, metrosil is connected across the relay , to drop the voltage.
1. PIC16F877A 2. CT 3.difference amplifier DIFFERENCE AMPLIFIER: To measure this current with pic microcontroller,we have to use ADC module of PIC microcontroller.To use ADC module we will convert current into voltage form by using a .1 ohm shunt resistor across CT and we will measure this voltage drop across shunt resistor.Then this voltage drop can be easily converted into current again.For example voltage drop across .1 ohm shunt resistor =8v then current according to ohm law V=IR I=V/R I=8/.1=8A but the problem is ADC of pic microcontroller can never measure voltage greater than 5 volt. so to solve this problem we can use differenceamplifier. By adjusting gain of difference amplifier we can reduce voltage lower than 5 volts.
No. A CVT (capacitor voltage transformer), like an voltage transformer, has a high primary impedance. the connections of a CT require the high voltage current to pass through the primary winding. This would result in significant loading of the circuit in question, at least until the CVT cooked.
A current transformer pushes a ratio of primary current in the secondary. A potential transformer pushes a ratio of primary voltage in the secondary. Shorting a CT allows the full current the CT wants to push to flow. Shorting a PT makes it very difficult for the PT to produce rated voltage. To keep the voltage at rated value, the PT would have to push ~infinite secondary current.
A current transformer (CT) is used to reduce a load current to a value that can be read by conventional instruments such as ammeters and wattmeters; it also enables the instruments to be located remotely. In the case of high-voltage circuits, a CT also electrically-isolates its burden (secondary load) from the primary circuit.
CT metering circuit can not be used to measure voltage
under internal fault conditions , CT primary current produces steep insrease in voltage across the relay. This will exceed the burden 3kv normally designed as per. To get protected from the voltage, metrosil is connected across the relay , to drop the voltage.
the Supreme Ct.
1. PIC16F877A 2. CT 3.difference amplifier DIFFERENCE AMPLIFIER: To measure this current with pic microcontroller,we have to use ADC module of PIC microcontroller.To use ADC module we will convert current into voltage form by using a .1 ohm shunt resistor across CT and we will measure this voltage drop across shunt resistor.Then this voltage drop can be easily converted into current again.For example voltage drop across .1 ohm shunt resistor =8v then current according to ohm law V=IR I=V/R I=8/.1=8A but the problem is ADC of pic microcontroller can never measure voltage greater than 5 volt. so to solve this problem we can use differenceamplifier. By adjusting gain of difference amplifier we can reduce voltage lower than 5 volts.
A CT becomes saturated when the induced secondary voltage is beyond the capabilities of the CT. Yes it is possible, if enough current is forced through the secondary to raise the voltage beyond the CT capability curve. Remember the CT has inherent resistance due to the secondary winding. That said, to saturate strictly based on the CT resistance is unlikely. But it is still theoretically possible.
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high voltage can be induced in the ct secondary which may sufficient to cause breakdown of insulation.
collector voltage wit respect to ground
No. A CVT (capacitor voltage transformer), like an voltage transformer, has a high primary impedance. the connections of a CT require the high voltage current to pass through the primary winding. This would result in significant loading of the circuit in question, at least until the CVT cooked.
A current transformer pushes a ratio of primary current in the secondary. A potential transformer pushes a ratio of primary voltage in the secondary. Shorting a CT allows the full current the CT wants to push to flow. Shorting a PT makes it very difficult for the PT to produce rated voltage. To keep the voltage at rated value, the PT would have to push ~infinite secondary current.
A current transformer (CT) is used to reduce a load current to a value that can be read by conventional instruments such as ammeters and wattmeters; it also enables the instruments to be located remotely. In the case of high-voltage circuits, a CT also electrically-isolates its burden (secondary load) from the primary circuit.
It means Current Transformer is used for measurement of electric currents, together with voltage transformers