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What is the amount of heat required in joules to heat 82g of water from 24C to 66C?
Wiki User
∙ 11y ago
Using the formula Q=mcΔT, the amount of heat energy required is (82g)(4.18J g-1 K-1)(42K) = 14400J.
Wiki User
∙ 11y ago
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How many joules are required to boil 21.1 g of water at 100 C?
The needed heat is 47,65 Joules.
Why is waters specific heat capacity 1.00 cal g C or 4.185 Joules g?
This is water's specific heat capacity because this is the amount of energy needed to heat up the water 1 degree Celsius.
What is the total amount of heat energy in joules absorbed by 25.0 grams of water when the temperature of the water increased from 24.0 C to 36.0 C?
2520 Joules = (X)(4.180J/gC)(30C-10C) 2520J = 83.6X 30.14 grams of water.
How much energy is required to heat 955 g of water from 20 degrees C to 100 degrees C?
4.1858 joules of energy will raise the temperature of 1 g of water by 1oC. Thus, 4.1858 * 955 * 80 = 319795.12 joules of energy is required to raise the temperature of 955 g of water by 1oC.
How many joules are required to melt 12.8 g of ice at 0 and degC?
To answer this, you need to know the ∆Hfusion of water, which happens to be 334 J/g. So, to melt 12.8 g of ice at 0ºC, the joules needed = (12.8 g)(334 J/g) = 4275 joules
Suppose you want to heat 40g of water by 20c how many joules of heat are required?
334.8 Joules
How many joules are required to boil 21.1 g of water at 100 C?
The needed heat is 47,65 Joules.
Which would require a greater amount of heat water or iron?
To raise the temperature of both an equal amount, water would require more energy. In terms of the energy required to raise the temperature: iron = 0.45 joules / gram . kelvin water = 4.2 joules / gram . kelvin This is known as the specific heat capacity of a material
How many watts of heat to raise 55.32 gallons of water to 160 degrees?
A watt is a unit of power: what is required is probably the amount of energy - which is measured in joules.
How many joules of energy are required to raise the temperature of 150.0g of water from 15.0 degrees C to 45.0 degrees C?
The specific heat capacity of water is 4186 joules per kilogram. That is to raise 1kg or 1 litre of water by 1 degree you will need to add 4186 joules of energy. So for 15grams over 25 degrees you will need 4186/1000*15*15 joules.
The amount of heat energy required to raise the temperature of one gram of water by one degrees celsius is?
4.184 joules. The is the specific heat or Cp of water is 4.184 J/mol.
What is an amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy?
The amount of water whose temperature would change by 15 degrees Celsius when it absorbs 2646 joules of heat energy is 42,2g H2O.
Suppose you want to heat 40 g of water by 20 degrees celsius how many joules of heat are required?
The heat required will be equal to 87.8 kJ.Energy = Specific heat capacity x mass x change in TemperatureQ = Cg x m x change T= 4.18 x 300 x 70= 87780 J= 87.8 kJDensity of water is 1.00 g / cm3Heat capacity of water = 4.18 J oC-1g-1
Suppose you want to heat 40g of water by 20 degrees Celsius how many joules of heat are required?
Use the equation q=mc(delta t) (that is, heat equals mass times specific heat times the change in temperature) to answer the question. The specific heat of water is 4.186 Joules per gram-Celsius. Therefore, q=(40)(4.186)(20), which equals 3348.8 Joules of heat (or approximately 3.35 kiloJoules of heat).
What happens to specific heat capacity if you remove a small amount of heat energy?
Nothing, the SHC refers to the amount of energy (joules) required to raise the temperature of 1 kg of the substance by 1 degree celcius
What is the difference between btus and joules?
1 BTU is the energy required to heat 1 pound of water by 1 degree F. 1 Joule is defined mechanically, but in thermal terms it is 1/4.2 of a calorie (4.2 Joules/calorie), and 1 calorie is the energy required to heat 1 gram of water by 1 degree C. In fact 1 BTU = 1055 Joules.
How many joules of energy are necessary to heat a sample of water with a mass of 46.0 grams from 0.0 celsius to 100.0?
419.1 Joules are required to heat one gram of liquid water from 0.01 degC to 100 deg C. So the answer is 419.1*46 = 19278.6
