the angular momentum is given by:
.
L = mass (m) * velocity (v) * radius (r)
you have the mass and radius, so to calculate the velocity:
.
circumference = 2 * pi * r = 2 * 3.1416 * 0.95 = 5.969 metres
14.7 rad / sec = 2.3396 rev / sec
so velocity = circumference * rev / sec = 2.3396 * 5.969 = 13.965 metres / sec.
so:
.
L = m * v * r = 0.73 * 13.965 * 0.95 = 9.685 n-m-s
Angular momentum is defined as the moment of linear momentum about an axis. So if the component of linear momentum is along the radius vector then its moment will be zero. So radial component will not contribute to angular momentum
-- tangential speed -- angular velocity -- kinetic energy -- magnitude of momentum -- radius of the circle -- centripetal acceleration
What we've got here is a particle rotating around an axis some distance fromit. So its angular momentum is ( r X m v ), and the fact that the particlehappens to be a ball is irrelevant.The vector cross-product just says that the direction of the angular momentumvector will be perpendicular to the plane of the rotation, which I don't think we careabout for purposes of this question. We're just looking for its magnitude . . . r m v .r = radius of the rotationm = massv = speed around the circle = ( ω r )r m v = (r m) (ωr) = m ω r2 = (0.210) (10.4) (1.1)2 = 2.64264 kg-m2/secI have no feeling for whether or not that's a reasonable result. I lost it aroundthe last time I had to calculate an angular momentum ... an event that wasroughly contemporaneous with the mass extinction of the dinosaurs.
The reason a skater spins faster when she pulls her arms in is because of angular momentum. It is measured by mass x velocity x radius. Bringing her arms in changes her radius and velocity.
A hockey puck of mass m = 0.25 kg is tied to a string and is rotating horizontally in a circle of radius R = 1.0 m on top of a frictionless table.
Angular momentum is defined as the moment of linear momentum about an axis. So if the component of linear momentum is along the radius vector then its moment will be zero. So radial component will not contribute to angular momentum
Angular velocity just means how fast it's rotating. If youaa want more angular velocity, just rotate it faster or decrease the radius (move it closer to the center of rotation). Just like force = rate of change of momentum, you have torque= rate of change of angular moment Or We can increase the angular velocity of a rotating particle by applying a tangential force(i.e. accelaration) on the particle. Since the velocity of the particle is tangential with the circle along which it is moving, the tangential accelaration will not change the diriction of the velocity(as angle is 0),but will cause a change in magnitude. Thus angular velocity will increase.
mass, velocity, and radius.
The radius of her path Her speedHer mass apex
The radius of her path Her speedHer mass apex
-- tangential speed -- angular velocity -- kinetic energy -- magnitude of momentum -- radius of the circle -- centripetal acceleration
What we've got here is a particle rotating around an axis some distance fromit. So its angular momentum is ( r X m v ), and the fact that the particlehappens to be a ball is irrelevant.The vector cross-product just says that the direction of the angular momentumvector will be perpendicular to the plane of the rotation, which I don't think we careabout for purposes of this question. We're just looking for its magnitude . . . r m v .r = radius of the rotationm = massv = speed around the circle = ( ω r )r m v = (r m) (ωr) = m ω r2 = (0.210) (10.4) (1.1)2 = 2.64264 kg-m2/secI have no feeling for whether or not that's a reasonable result. I lost it aroundthe last time I had to calculate an angular momentum ... an event that wasroughly contemporaneous with the mass extinction of the dinosaurs.
10/3
The reason a skater spins faster when she pulls her arms in is because of angular momentum. It is measured by mass x velocity x radius. Bringing her arms in changes her radius and velocity.
The radius of a circle has no bearing on the angular measure of the arc: the radius can have any positive value.
To convert linear speed to angular speed, divide the linear speed by the radius of the rotating object. The formula for this relationship is: angular speed (ω) = linear speed (v) / radius (r). This will give you the angular speed in radians per second.
A hockey puck of mass m = 0.25 kg is tied to a string and is rotating horizontally in a circle of radius R = 1.0 m on top of a frictionless table.