That's a true statement.
What is the question ?
Speed = (acceleration) times (time)Acceleration = gravity = 9.8 meters (32.2 feet) per second2Speed = 10g = 98 meters (322 feet) per second
Acceleration = change in velocity/time a = (v - u) /t where a= acceleration, v= velocity, u= initial velocity & t= time. u = 121 m/s v = 98 m/s t = 12 m/s a = (98 - 121) /12 a = -23/12 a = -1.91667 m/s2
Average acceleration during the time interval = (change on speed) / (time for the change) =(98 - 121) / (12) = -23/12 = negative (1 and 11/12) meters per second2
b. -1.92 m/s2Minutes per second is not a unit of velocity. If the question meant meters per second, the answer is correct.
30.990 metres/sec
Speed = (acceleration) times (time)Acceleration = gravity = 9.8 meters (32.2 feet) per second2Speed = 10g = 98 meters (322 feet) per second
Acceleration = change in velocity/time a = (v - u) /t where a= acceleration, v= velocity, u= initial velocity & t= time. u = 121 m/s v = 98 m/s t = 12 m/s a = (98 - 121) /12 a = -23/12 a = -1.91667 m/s2
No, that's not correct.The acceleration of gravity means that for each second that passes, falling objects fallat a speed that's 9.8 meters per second fasterthan it was one second earlier.
Average acceleration during the time interval = (change on speed) / (time for the change) =(98 - 121) / (12) = -23/12 = negative (1 and 11/12) meters per second2
b. -1.92 m/s2Minutes per second is not a unit of velocity. If the question meant meters per second, the answer is correct.
30.990 metres/sec
No
98 inches = 2.4892 meters.
98 meters = 321.52231 feet
The elevator is accelerating downwards at g / 10 or ~3.2 ft/sec/sec (.98 m/sec/sec) note. the question shows that the weighing took place on a bathroom scale or a spring balance. If you used a beam balance or a steelyard you would always measure 100lbs.
98 meters = 98,000 millimeters
Where: vi is the initial velocity of the rock [0 meters/second] a is the acceleration of the rock [-9.81 meters/second2] s is the final position of the rock [0 meters] si is the initial position of the rock [98 meters] v is the velocity of the rock when it hits the water If you plug in all of the numbers and solve for v, you should get the rock to be traveling at 43.84929 meters per second when it hits the water. Or if your rounding it is 43.8