By Kirchhoff's Voltage Law, the sum of the voltage drops around the series circuit will equal the voltage applied to the circuit.
The voltage is greater than the applied voltage, why?
Ohm's law states that the current in a circuit is inversely proportional to the circuit resistance. There is a single path for current in a series circuit. The amount of current is determined by the total resistance of the circuit and the applied voltage.
Amps Ohm's law states the current is directly proportional to the applied emf (voltage) and inversely proportional to the resistance of the circuit.
no
.2A
Correct Answer= "the current will increase"
POWER, P=V*Iif, P=10w,I=5AP=>10W = V * 510=5VV=2volts
Any voltage that is fed into or "applied" to an electrical circuit is referred to as an "applied voltage".
For a series circuit, the applied voltage equals the sum of the voltage drops
this is the amount of voltage a circuit can hold.
When an alternating voltage is applied to a purely resistive circuit, the resulting current is in phase with the voltage.
EMF (voltage) is the force that keeps current flowing in a circuit.
The applied voltage is 53+28 = 81V.
By Kirchhoff's Voltage Law, the sum of the voltage drops around the series circuit will equal the voltage applied to the circuit.
Voltage is equal to the Current multiplied by the Resistance.Without changing the resistance, increasing the applied voltage in a circuit will increase current flow. There is a simple, direct relationship between voltage and current. Double the voltage, twice the current will flow. Triple the voltage, and the current will triple. As voltage (E) equals current (I) times resistance (R), when resistance is fixed, what happens to voltage will happen to current.
The voltage is greater than the applied voltage, why?