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a*% abundace + b*%abundance + c*%abundance
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What is the average atomic mass of an element with isotopes a b and c?
(mass of A) x (%of A) + (mass of B) x (% of B) + (mass of C) x (% of C)
Why do elements which exists as isotopes have fractional atomic mass?
Each isotope of an element has a different Atomic Mass, so an average is taken of all the isotopes, but the average is weighted because the natural abundance (%) of each isotope is factored in. If hydrogen-1 is much more abundant than deuterium and tritium, then the weighted average will be closer to 1 than 2 or 3 but not a whole number. The following equation shows how percent abundance factors into the weighted average. (atomic mass A)(X% abundance) + (atomic mass B)(Y% abundance)...=(weighted average of all isotopes of the element)(100% abundance)
Each element has its own characteristic atom in which a. the atomic weight is constant b. the atomic number is constant c. the mass number is constant?
b. the atomic number is constant. The mass number is not constant because there are isotopes of an element that have the same number of protons but different number of neutrons. Likewise, there are isotopes of the same element with different atomic weights.
The atomic mass is equal to the sum of?
The Atomic Mass number of an element is the sum of the protons and neutrons in the nucleus of an atom of that element.The relative atomic mass is the average atomic mass number of all the known isotopes of an element.
Why does a mass of an atom changes if it an isotope?
yes it does b/c the isotopes have different number of neutrons so therefore isotopes cause a change in mass.
What is average atomic mass of an element with isotopes A B and C?
(mass of A) x (%of A) + (mass of B) x (% of B) + (mass of C) x (% of C)
What is the average atomic mass of an element with isotopes a b c?
(mass of A) x (%of A) + (mass of B) x (% of B) + (mass of C) x (% of C)
What is the average atomic mass of an element with isotopes a b and c?
(mass of A) x (%of A) + (mass of B) x (% of B) + (mass of C) x (% of C)
Why do elements which exists as isotopes have fractional atomic mass?
Each isotope of an element has a different Atomic Mass, so an average is taken of all the isotopes, but the average is weighted because the natural abundance (%) of each isotope is factored in. If hydrogen-1 is much more abundant than deuterium and tritium, then the weighted average will be closer to 1 than 2 or 3 but not a whole number. The following equation shows how percent abundance factors into the weighted average. (atomic mass A)(X% abundance) + (atomic mass B)(Y% abundance)...=(weighted average of all isotopes of the element)(100% abundance)
The average atomic mass of boron is 10.81 amu. Based on the atomic mass of B-10 and the relative abundances of the boron isotopes what is the atomic mass of B-11?
B-10 is 10.013
Each element has its own characteristic atom in which a. the atomic weight is constant b. the atomic number is constant c. the mass number is constant?
b. the atomic number is constant. The mass number is not constant because there are isotopes of an element that have the same number of protons but different number of neutrons. Likewise, there are isotopes of the same element with different atomic weights.
The atomic mass is equal to the sum of?
The Atomic Mass number of an element is the sum of the protons and neutrons in the nucleus of an atom of that element.The relative atomic mass is the average atomic mass number of all the known isotopes of an element.
Why does a mass of an atom changes if it an isotope?
yes it does b/c the isotopes have different number of neutrons so therefore isotopes cause a change in mass.
What is the formula to figure out the weighted average of something?
Lets say there are 3 isotopes of an element. A is 25% and has a mass of 24, B is 40% and has a mass of 25, and C is 35% and has a mass of 26. Multiply the mass by the percentage in decimal form and add all together. (.25 x 24) + (.40 x 25) + (.35 x 26) = weighted average. If there are more then continue (percent in decimal form x mass) and keep adding.
What is the basic difference between isotopes of the same element other than atomic mass?
There r no differences but in sm elements the difference can b of radioactivity like in calcium(ca).
There are no known stable isotopes of the element with an atomic number of a 56 B 38 C100 D 20?
Element 20 is Tin. Element 38 is Strontium. Element 56 is is Barium. Element 100 Fermium. Fermium is artificially created, and has no stable isotopes. In general, there are no stable isotopes heavier than Bismuth (element 83).
As an element occurs as a mixture of naturally occurring isotopes what is the atomic mass of the element based upon?
The atomic mass of an element is based upon the weighted average of the atomic masses of the naturally occurring isotopes of that element. We need to know what isotopes of a given element occur in nature, and what percentage of the natural abundance of an element each of those naturally occurring isotopes represents. What that means might be more easily seen if we just run through some examples. So let's run through some.We have an element with 3 naturally occurring isotopes. They occur equally. That is, each one represents a third of the natural atoms, or 33 1/3 % of them. If the atomic masses of our isotopes are 17, 18 and 19, and all occur equally, then it's 17 + 18 + 19 (which equals 54) divided by 3 which is 54 divided by 3 which is 18. Our atomic mass for the element cited is 18, and that represents all the natural isotopes and the percentage in which they occur. Pretty easy.We have an element with 4 naturally occurring isotopes. Here are their atomic masses and percent abundance: a = 46 (25%), b = 47 (50%), c = 48 (15%), and d = 49 (10%). There is a (fairly) simple process one can use to find the weighted average. Multiply the percent natural abundance times the atomic mass of each one and add them all together. Not to difficult, is it? Roll up your sleeves and let's have at it.46 x 25% = 11.547 x 50% = 23.548 x 15% = 7.249 x 10% = 4.911.5 + 23.5 + 7.2 + 4.9 = 47.1 atomic mass unitsSo now we have our atomic mass for our mystery element in example two. We calculated it by determining a weighted average of the naturally occurring isotopes. And that's very important information to take to the lab where we'll be measuring (weighing) some of this stuff.
