2H3PO4(aq) + 3Ba(OH)2(aq) > Ba3(PO4)2(aq) + 6H2O(l)
The equation is , Ba(OH)2 + 2HCl = BaCl2 + 2H2O
The balanced chemical equation for the reaction between barium nitrate and sodium hydroxide is: Ba(NO₃)₂ + 2NaOH → Ba(OH)₂ + 2NaNO₃
The ionic equation for phosphoric acid (H3PO4) and barium hydroxide (Ba(OH)2) is: 3H+ + 2OH- -> 3H2O This equation represents the neutralization reaction that occurs between the acid and base to form water.
Ba(OH)2 + 2HNO3 -------> Ba(NO3)2 +2H2O
Ba(OH)2(hydroxide) + H2SO4(acid) ==> BaSO4(salt) + 2H2O(water)
The balanced chemical equation for the reaction between barium nitrate (Ba(NO3)2) and potassium hydroxide (KOH) is: Ba(NO3)2 + 2KOH -> Ba(OH)2 + 2KNO3
The balanced equation for barium peroxide is: BaO2 -> BaO + 1/2 O2
This equation is Ba(OH)2 + H2SO4 -> BaSO4 + H2O.
Barium sulphate to barium sulphate is NO CHANGE!
Barium peroxide (BaO) decomposes in water to barium oxide and oxygen. Barium oxide will further react with water to produce barium hydroxide. Summing up: 2BaO+2H2O-->2Ba(OH)2+02
The reaction between ammonium phosphate and barium hydroxide will produce barium phosphate and ammonium hydroxide as products. This is a double displacement reaction where the cations and anions switch partners. The balanced chemical equation for this reaction is: (NH4)3PO4 + 3Ba(OH)2 → Ba3(PO4)2 + 6NH4OH.
Ba is Barium, OH is Hydroxide and the 8 H2O is Octahydrate. This results in Barium Hydroxide Octahydrate.