No.
for a start you have potassium on one side (K) and sodium on the other (Na) and what has happened to the Oxygen (O).
Your chemical equation does not make any sense.
No, the equation is not balanced. The correct balanced equation would be: 2Na + F2 -> 2NaF
The balanced equation for the reaction between sodium metasilicate (Na2SiO3) and hydrofluoric acid (HF) to produce hexafluorosilicic acid (H2SiF6), sodium fluoride (NaF), and water (H2O) is: 3Na2SiO3 + 12HF → 2H2SiF6 + 6NaF + 9H2O
The chemical equation is:MgF2 + 2 Na = 2 NaF
The elements involved in this reaction are sodium (Na) and magnesium (Mg). The reaction occurs between solid sodium (Na) and solid magnesium fluoride (MgF2) to form solid sodium fluoride (NaF) and solid magnesium (Mg).
You think probable to sodium fluoride , NaF.
No, the equation is not balanced. The correct balanced equation would be: 2Na + F2 -> 2NaF
The balanced equation for the reaction between sodium metasilicate (Na2SiO3) and hydrofluoric acid (HF) to produce hexafluorosilicic acid (H2SiF6), sodium fluoride (NaF), and water (H2O) is: 3Na2SiO3 + 12HF → 2H2SiF6 + 6NaF + 9H2O
Flourine has a charge of -1 and sodium has a charge of +1. Together they are equivalent to 0, so they are already perfectly balanced. An empirical formula is just a way to express the "smallest" balanced ratio. and since you can't get any smaller or more basic than 1 NA and 1 F, your empirical formula is just that: NaF.
The balanced equation for fluorine reacting with sodium iodide is: 2 NaI + F2 → 2 NaF + I2
Yes, this reaction is possible. Fluorine will displace chlorine from some compounds.
The balanced chemical equation for the reaction between sodium and fluorine to produce sodium fluoride is: 2 Na + F2 -> 2 NaF This equation is balanced because there are equal numbers of each type of atom on both the reactant and product sides of the equation.
The balanced chemical equation for the reaction between sodium chloride and fluorine to form sodium fluoride and chlorine is: 2 NaCl + F2 → 2 NaF + Cl2.
Sodium fluoride dissolves in water but does not chemically react with water.
2NaCl + F2 -> 2NaF + Cl2 The first F in the equation has 2, so the second has to have 2 as well. But placing a 2 before the NaF, gives the Na 2. So add a 2 before the NaCl. and the Cl after the yield sign already has 2.
The balanced chemical equation for the reaction between sodium chloride (NaCl) and elemental fluorine (F2) to form sodium fluoride (NaF) and chlorine gas (Cl2) is: 2 NaCl + F2 -> 2 NaF + Cl2
The chemical equation is:MgF2 + 2 Na = 2 NaF
MgCl2(soln) + 2NaF(soln) ------> MgF2(s) + 2NaCl(aq)