No.
for a start you have potassium on one side (K) and sodium on the other (Na) and what has happened to the Oxygen (O).
Your chemical equation does not make any sense.
2Na + F2 g 2NaF
It's been awhile since I did one of these, but I think it's: Na2SiO3 + 8HF produces H2SiF6 + 2NaF + 3H2O
Yes
The chemical equation is:MgF2 + 2 Na = 2 NaF
HCl + NaF -> HF + NaCl
no 2Na (s) + MgF2 ? 2NaF (s) + Mg (s) is balanced apex
It's been awhile since I did one of these, but I think it's: Na2SiO3 + 8HF produces H2SiF6 + 2NaF + 3H2O
Flourine has a charge of -1 and sodium has a charge of +1. Together they are equivalent to 0, so they are already perfectly balanced. An empirical formula is just a way to express the "smallest" balanced ratio. and since you can't get any smaller or more basic than 1 NA and 1 F, your empirical formula is just that: NaF.
Yes
Yes, this reaction is possible. Fluorine will displace chlorine from some compounds.
The chemical equation is:MgF2 + 2 Na = 2 NaF
HCl + NaF -> HF + NaCl
NaF sorry all i know
2NaCl + F2 -> 2NaF + Cl2 The first F in the equation has 2, so the second has to have 2 as well. But placing a 2 before the NaF, gives the Na 2. So add a 2 before the NaCl. and the Cl after the yield sign already has 2.
no 2Na (s) + MgF2 ? 2NaF (s) + Mg (s) is balanced apex
The balanced chemical equation for the reaction is BaCl2(aq) + 2 NaF(aq) → BaF2(s) + 2 NaCl(aq)
2Na2S2O3 + I2 --> 2NaI + Na2S4O6
This reaction is:2 F2 + 4 NaOH = 4 NaF + 2 H2O + O2