Yes, this reaction is possible. Fluorine will displace chlorine from some compounds.
When chlorine gas (Cl2) reacts with dilute sodium hydroxide (NaOH), it forms sodium hypochlorite (NaOCl) and sodium chloride (NaCl), along with water (H2O). The reaction can be represented as Cl2 + 2NaOH -> NaOCl + NaCl + H2O.
HCl + NaOH = H2O + NaCl is already balanced.
NaClO3 + 6 HCl = 3 Cl2 + 3 H2O + NaCl
The balanced chemical equation for the reaction between sodium chloride and fluorine to form sodium fluoride and chlorine is: 2 NaCl + F2 → 2 NaF + Cl2.
To find the grams of NaCl with 2.34 moles of Cl2, you need to consider the molar ratio. For every 1 mole of Cl2, there are 2 moles of Cl in NaCl. So, 2.34 moles of Cl2 would be equivalent to 4.68 moles of Cl in NaCl. Using the molar mass of NaCl (58.44 g/mol), you can calculate that 4.68 moles of NaCl would be approximately 273.64 grams.
No, the reaction Br2 + NaCl → NaBr + Cl2 does not occur. The correct reaction between Br2 and NaCl is 2NaBr + Cl2.
Any reaction occur.
Sodium chloride dissolved in water form a solution.
This is a single replacement reaction where chlorine (Cl2) displaces bromine in sodium bromide (NaBr) to form sodium chloride (NaCl) and bromine gas (Br2).
single replacement
When chlorine gas (Cl2) reacts with dilute sodium hydroxide (NaOH), it forms sodium hypochlorite (NaOCl) and sodium chloride (NaCl), along with water (H2O). The reaction can be represented as Cl2 + 2NaOH -> NaOCl + NaCl + H2O.
HCl + NaOH = H2O + NaCl is already balanced.
NaClO3 + 6 HCl = 3 Cl2 + 3 H2O + NaCl
Cl2 is covalent. NaCl is ionic.
The molar ratio of Cl2 to NaCl is 1:2, so for every 1 mole of Cl2, 2 moles of NaCl are produced. To find the amount of NaCl produced from 13g of Cl2, first calculate the number of moles of Cl2 using its molar mass, then use the mole ratio to determine the moles of NaCl, and finally convert to grams of NaCl.
4
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)