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By this, I assume you mean, the chemical reaction. If this is the case, the answer is 2I +2NaCl
Cl2(g) + 2KI --> 2KCl(aq) + I2(s)
2KI + Cl2 = 2KCl + I2
The reaction is:Cl2 + 2 Ki = 2 KCl + I2
The balanced equation for the reaction between sodium (Na) and chlorine (Cl2) to form sodium chloride (NaCl) is 2Na + Cl2 -> 2NaCl. This equation is balanced because it has an equal number of each type of atom on both sides of the reaction arrow.
To balance the reaction Cl2 + KI -> KCl + I2, you just need to place a coefficient of 2 in front of KCl to balance the number of chlorine atoms on both sides of the reaction. The balanced reaction is Cl2 + 2KI -> 2KCl + I2.
The balanced equation for fluorine reacting with sodium iodide is: 2 NaI + F2 → 2 NaF + I2
To balance the chemical equation Na + I2 -> NaI, you need to ensure that there is an equal number of atoms of each element on both sides of the equation. In this case, you would need to put a coefficient of 2 in front of NaI to balance the equation.
When sodium hypochlorite (NaClO) reacts with potassium iodide (KI), it forms potassium chloride (KCl), sodium iodide (NaI), and elemental iodine (I2). This reaction can be represented by the equation: 3NaClO + 2KI → KCl + NaCl + NaI + I2.
No reaction occurs girlsnotgrey: If you look at the periodic table for the the halogens the F, Cl, Br, I Chloride is higher up on the periodic table then Iodine. Meaning that Chlorine is more reactive then Iodine. so when Iodine is mixed with sodium chloride, Chloride will stay with sodium and there will be no reaction. NaCl(aq)+I(aq)= NaCl(aq) +I(aq) as you can see there is no reaction so you just write no reaction.
This is a double displacement reaction, also known as a metathesis reaction. In this reaction, the chlorine atoms in Cl2 and the iodide ions in KI swap partners to form potassium chloride (KCl) and iodine (I2).
Cl2 stands for Chlorine.I2 stands for Iodine.