No reaction occurs
girlsnotgrey:
If you look at the Periodic Table for the the halogens
the F, Cl, Br, I
Chloride is higher up on the periodic table then Iodine. Meaning that Chlorine is more reactive then Iodine. so when Iodine is mixed with sodium chloride, Chloride will stay with sodium and there will be no reaction.
NaCl(aq)+I(aq)= NaCl(aq) +I(aq)
as you can see there is no reaction so you just write no reaction.
I am currently a TA for a College chemistry department... I came across an assignment with the same problem and the Answer key seemed to be wrong in my opinon. They had NaI + Cl2 -> NaCl + I2 which to me doesn't seem to be balanced... in my opinion the correct balance of this equation should be 2NaI + Cl2 -> 2NaCl + I2 but its up to you which one you think it is. Hope this helps
sodium iodide + chlorine = sodium chloride + iodine
The equation for the reaction of chlorine with sodium iodide is as follows:
Cl2 + 2NaI --> 2NaCl + I2
In this reaction, chlorine oxidizes iodide ions to iodide.
2NH4I + Cl2 = 2NH4Cl + I2
you have to write... 2KI + Cl2 = 2KCl + I2
2KI + Cl2 = 2KCl + I2
Unbalanced: KBr + BaI2 --> KI + BaBr2Balanced: 2KBr + BaI2 --> 2KI + BaBr2
48.5
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
Cl2(g) + 2NaI(s) --------> 2NaCl(s) + I2(s)
Iodide ions reacts with Chlorine to form elementary Iodine and Chloride ions
Potassium iodide
The chemical reaction is:2 HI + Br2 = 2 HBr + I2
you have to write... 2KI + Cl2 = 2KCl + I2
The chemical equation is:2 KI + Pb(NO3)2 = 2 KNO3 + PbI2(s)
2KI + Cl2 = 2KCl + I2
potassium iodide
Unbalanced: KBr + BaI2 --> KI + BaBr2Balanced: 2KBr + BaI2 --> 2KI + BaBr2
The chemical equation is:2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2
Equation: O22- + I- ----> O2- + I2
48.5