This app is trash
2NaCl + F2 -> 2NaF + Cl2 The first F in the equation has 2, so the second has to have 2 as well. But placing a 2 before the NaF, gives the Na 2. So add a 2 before the NaCl. and the Cl after the yield sign already has 2.
F2 + 2 KCl -------> 2 KF + Cl2
2 Na + F2 --> 2 NaF It is one of the most violent reactions between two elements.
Single replacement.
H2, N2, O2, F2, Cl2, Br2, and I2 are all diatomic elements.
2NaCl + F2 -> 2NaF + Cl2 The first F in the equation has 2, so the second has to have 2 as well. But placing a 2 before the NaF, gives the Na 2. So add a 2 before the NaCl. and the Cl after the yield sign already has 2.
F2 + 2 NaCl = 2 NaF + Cl2
The reaction i the following:2 NaCl + F2 = 2 NaF + Cl2
Yes, this reaction is possible. Fluorine will displace chlorine from some compounds.
That is the (unbalanced) equation (substituting the "and" with an arrow) of the combination of salt and fluorine to create sodium fluoride and chlorine gas. Or...2NaCl + F2 → 2NaF + Cl2↑Sodium chloride + fluorine → sodium fluoride + chlorine gas
Flourine has a charge of -1 and sodium has a charge of +1. Together they are equivalent to 0, so they are already perfectly balanced. An empirical formula is just a way to express the "smallest" balanced ratio. and since you can't get any smaller or more basic than 1 NA and 1 F, your empirical formula is just that: NaF.
Cl2
F2 + 2 KCl -------> 2 KF + Cl2
I2 is deep purple color. Br2 is a reddish brown, Cl2 is a green. F2 is yellow.
Single replacement. The F2 replaces Cl to form HF and Cl2.
2 Na + F2 --> 2 NaF It is one of the most violent reactions between two elements.
Yes