This equation is 2 HCl + CuO -> CuCl2 + H2O.
CuO + 2HCl --> CuCl2 + H2O
Balanced equation: CuO + 2HCl --> CuCl2 + H2O Word equation: One mole of copper (II) oxide plus two moles of hydrochloric acid produces (or yields) one mole of copper (II) chloride plus one mole of water.
The balanced equation for copper(II) oxide and potassium chloride is CuO + 2KCl → CuCl2 + K2O When copper(II) oxide reacts with potassium chloride then it forms copper(II) chloride and potassium oxide.
CuO(s) + 2HCl(aq) --> CuCl2(aq) + H2O(l) Copper oxide + Hydrochloric Acid --> Copper Chloride + Water
The balanced symbol equation for copper II oxide reacting with hydrogen is Cu + H2O. This reaction will create copper and water as a result.
The balanced symbol equation for copper reacting with oxygen to form copper oxide is: 4Cu + O2 → 2Cu2O
This will depend upon which version of copper oxide you have - copper I oxide or copper II oxide. For copper I oxide: H2SO4 + Cu2O --> Cu2SO4 + H2O For copper II oxide: H2SO4 + CuO --> CuSO4 + H2O
Copper oxide and hydrochloric acid will produce copper chloride.
2Cu + O2 yields 2CuO
Yes copper oxide reacts with hydrochloric acid and it forms a blue green compound.
Balanced equation of nitric oxide is no3 2-
The balanced chemical equation for the reaction between copper(II) oxide (CuO) and sulfuric acid (H2SO4) is: CuO + H2SO4 → CuSO4 + H2O