CuSO4 * 5H2O
The chemical formula (not equation) is CuSO4.5H2O.
The balanced chemical equation for copper sulfate is: CuSO4 + H2O → CuSO4•5H2O
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
The balanced chemical equation for the decomposition of copper (II) sulfate pentahydrate ((CuSO_4 \cdot 5H_2O)) is: [CuSO_4 \cdot 5H_2O \rightarrow CuSO_4 + 5H_2O] This equation represents the decomposition of copper (II) sulfate pentahydrate into copper (II) sulfate and water. The balanced equation shows that one mole of copper (II) sulfate pentahydrate decomposes into one mole of copper (II) sulfate and five moles of water.
This equation is CuSO4.5 H2O -> CuSO4 + 5 H2O.
The anhydrous copper(II) sulfate is white, the pentahydrate is blue.Iron is gray.
Let the fourmula for the hydrous copper sulphate be CuSO4XH20 where X represents the number of water molecules write a balanced equation for the heating of the blue copper sulphate crystals?
When copper sulfate pentahydrate is heated, it undergoes a dehydration reaction where the water molecules are released, leaving behind anhydrous copper sulfate. This process is reversible, and when anhydrous copper sulfate is exposed to moisture, it will reabsorb water and form copper sulfate pentahydrate again.
When heating copper(II) sulfate pentahydrate, the water molecules in the crystal structure are removed, leaving anhydrous copper(II) sulfate. The balanced chemical equation for this reaction is CuSO4·5H2O(s) → CuSO4(s) + 5H2O(g).
Compounds with .H2O are termed as hydrated compounds..5H2O is pentahydrate.So the name is Copper sulphate pentahydrate
CuSO4•5H2O + heat ---> CuSO4 + 5H2O
The chemical formula for blue vitriol (copper sulphate pentahydrate) is CuSO4.