This equation is 2 HCl + CuO -> CuCl2 + H2O.
CuO + 2HCl --> CuCl2 + H2O
Balanced equation: CuO + 2HCl --> CuCl2 + H2O Word equation: One mole of copper (II) oxide plus two moles of hydrochloric acid produces (or yields) one mole of copper (II) chloride plus one mole of water.
CuO(s) + 2HCl(aq) --> CuCl2(aq) + H2O(l) Copper oxide + Hydrochloric Acid --> Copper Chloride + Water
The balanced equation for copper(II) oxide and potassium chloride is CuO + 2KCl → CuCl2 + K2O When copper(II) oxide reacts with potassium chloride then it forms copper(II) chloride and potassium oxide.
The balanced symbol equation for copper II oxide reacting with hydrogen is Cu + H2O. This reaction will create copper and water as a result.
This will depend upon which version of copper oxide you have - copper I oxide or copper II oxide. For copper I oxide: H2SO4 + Cu2O --> Cu2SO4 + H2O For copper II oxide: H2SO4 + CuO --> CuSO4 + H2O
Copper oxide and hydrochloric acid will produce copper chloride.
2Cu + O2 yields 2CuO
Yes copper oxide reacts with hydrochloric acid and it forms a blue green compound.
Balanced equation of nitric oxide is no3 2-
CuO + H2SO4 --> CuSO4 + H2O
acid + metal oxide -> metal salt + water hydrochloric acid + calcium oxide -> calcium chloride + water 2HCl (aq) + CaO (s) -> CaCl2 (s) + H2O (l)