You did not mention whether iron(II) nitrate or Iron(III) nitrate in the question. I assume it as iron(III) nitrate and here is the answer. Fe(NO3)3(aq) + 3 NaOH(aq) --> Fe(OH)3(s) + 3 NaNO3(aq)
That's a double replacement reaction, and the products will be iron(III) nitrate and sodium chloride. Here's the balanced equation:
FeCl3 + 3NaNO3 --> Fe(NO3)3 + 3NaCl
Fe(NO3)3 (aq) + 3 Na(OH) (s) ----> Fe(OH)3 (s) + 3 NaNO3 (aq)
2 Fe(NO3)3(aq) + 3 Na2CO3(aq) ---> Fe2(CO3)3(s) + 6 NaNO3(aq)
Fe+3 + 3OH-1 + 3Na+1 + 3NO3-1 --> Fe(OH)3 + 3NaNO3
Full Equation
Fe(NO3)3(aq) + 3NaOH(aq) --> Fe(OH)3(s) + 3NaNO3(aq)
Net Ionic Equaton
Fe3+(aq) + 3OH-(aq) --> Fe(OH)3(s)
FeCl2 + 2NaOH -> 2NaCl + Fel(OH)2
it produces ammonia (NH3) and water; the nitrate and sodium ions are spectator ions and do not participate in the reaction. Hence, ionic equation: NH4+ + OH- -> NH3 + H2O
All elements are disassociated so there is no net Ionic equation
Stardust
There is none because they cancel out.
NaOH + HCL --> NaCl + H20 The basic equation is as follows: NaOH(aq) + HCl(aq) -----------> NaCl(aq) + H20(l) sodium hydroxide + hydrochloric acid ----> Sodium chloride + water. The molecules themselves dissociate in an equilibrium and so the ionic equation is: H+(aq) + Cl-(aq) + Na+(aq) + OH-(aq) ---------> Na+(aq) + Cl-(aq) + H2O(l). hope that helps
it produces ammonia (NH3) and water; the nitrate and sodium ions are spectator ions and do not participate in the reaction. Hence, ionic equation: NH4+ + OH- -> NH3 + H2O
The net ionic equation is Ag+(aq) + I- --> AgI(s) The sodium (Na+) and nitrate (NO3-) are spectators as always.
All elements are disassociated so there is no net Ionic equation
There isn't one as these two compounds do not react with each other.
Pb2+ + SO42- --> PbSO4
Stardust
Dissolving is not a chemical reaction; any chemical equation.
There is none because they cancel out.
SO42- + Ba2+ --> BaSO4
NaOH + HCL --> NaCl + H20 The basic equation is as follows: NaOH(aq) + HCl(aq) -----------> NaCl(aq) + H20(l) sodium hydroxide + hydrochloric acid ----> Sodium chloride + water. The molecules themselves dissociate in an equilibrium and so the ionic equation is: H+(aq) + Cl-(aq) + Na+(aq) + OH-(aq) ---------> Na+(aq) + Cl-(aq) + H2O(l). hope that helps
Sodium hydroxide has ionic bonds. A compound never is any kind of bond.
CO3-2+2Ag+ produces Ag2CO3 when writing ionic equation place arrow instead of the word produces