cuso4 - 5h2o= cuso4 + 5h20 + heat
Describe the appearance and odor of the liquid obtained by heating copper II sulfate pentahydrate.
The reaction is dehydration.
The percentage of water in copper(II) sulfate pentahydrate is 36,04 %.
Copper sulfate is normally found in the form of blue crystals, copper (II) sulfate pentahydrate. When you heat copper sulfate pentahydrate it turns white as the water which is driven off by the heat. The white solid remaining is anhydrous copper sulfate. If you add water to the anhydrous copper sulfate an exothermic reaction occurs, you can feel the test-tube getting hot, as the blue copper sulfate pentahydrate is re-formed.
The chemical formula for blue vitriol (copper sulphate pentahydrate) is CuSO4.
This equation is CuSO4.5 H2O -> CuSO4 + 5 H2O.
CuSO4•5H2O + heat ---> CuSO4 + 5H2O
CuSO4 * 5H2O
There is a balanced equation to use for decomposition of copper II sulfate pentahydrate. It is the following: CuSO4.5H2O+heat -->CuSO4(anhydrous)+5H2O.
Compounds with .H2O are termed as hydrated compounds..5H2O is pentahydrate.So the name is Copper sulphate pentahydrate
a copper sulfate solution it becomes copper (II) sulfate pentahydrate
The primary hydrate of copper sulfate is the pentahydrate of copper (II) sulfate, with formula CuSO4.5 H2O.
The chemical formula (not equation) of copper(II) sulfate is CuSO4.
Describe the appearance and odor of the liquid obtained by heating copper II sulfate pentahydrate.
Yes it is
Physical
The reaction is dehydration.