H3PO4 + Al(OH)3 ---> 3H2O + AlPO4
The balanced equation for the neutralization reaction between hydrochloric acid (HCl) and lithium hydroxide (LiOH) is: HCl + LiOH -> LiCl + H2O
The balanced equation for the reaction between aluminum hydroxide and permanganic acid is: 2Al(OH)3 + 5H2MnO4 -> 2Al(MnO4)3 + 6H2O + 5MnO2
The balanced neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) in aqueous solution is: H2SO4 + 2KOH -> K2SO4 + 2H2O
Aluminium Sulphate and potassium hydroxide. Al2(SO4)3 + 6KOH = 3K2(SO4) + 2Al(OH)3
Aluminum hydroxide is a base, while nitric acid is a acid (obviously). Therefore, they would cause a neutralization reaction, which form water and a salt. The equation would look like this:Al(OH)3 + 3HNO3 -> 3H2O + Al(NO3)3
The balanced equation for the neutralization reaction between hydrochloric acid (HCl) and lithium hydroxide (LiOH) is: HCl + LiOH -> LiCl + H2O
The balanced equation for the reaction between aluminum hydroxide and permanganic acid is: 2Al(OH)3 + 5H2MnO4 -> 2Al(MnO4)3 + 6H2O + 5MnO2
The balanced neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) in aqueous solution is: H2SO4 + 2KOH -> K2SO4 + 2H2O
To find the grams of aluminum hydroxide from 15.7 grams of aluminum sulfide, you first need to balance the chemical equation. The balanced equation is 2Al2S3 + 6H2O -> 4Al(OH)3 + 3H2S. Next, calculate the molar mass of aluminum sulfide (Al2S3) and aluminum hydroxide (Al(OH)3), then use the stoichiometry from the balanced equation to find the grams of aluminum hydroxide produced.
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
Aluminium Sulphate and potassium hydroxide. Al2(SO4)3 + 6KOH = 3K2(SO4) + 2Al(OH)3
Aluminum hydroxide is a base, while nitric acid is a acid (obviously). Therefore, they would cause a neutralization reaction, which form water and a salt. The equation would look like this:Al(OH)3 + 3HNO3 -> 3H2O + Al(NO3)3
The complete neutralization of potassium hydroxide (KOH) with hydrochloric acid (HCl) results in the formation of potassium chloride (KCl) and water (H2O). The balanced chemical equation for this reaction is: KOH + HCl -> KCl + H2O.
Al(NO3)3 + 3 NaOH --> Al(OH)3 + 3 NaNO3
When sodium hydroxide reacts with methanol, a neutralization reaction occurs, forming sodium methoxide and water. The balanced chemical equation for this reaction is: CH3OH + NaOH → CH3ONa + H2O
(*Warning!!Xb42 is a atomic chemical,so do not mix aluminum oxide and dilute potassium hydroxide!!*)
The products of a neutralization reaction between sulfuric acid and potassium hydroxide are potassium sulfate and water. The balanced chemical equation for this reaction is H2SO4 + 2KOH -> K2SO4 + 2H2O.