The balanced equation for the reaction between aluminum hydroxide and permanganic acid is:
2Al(OH)3 + 5H2MnO4 -> 2Al(MnO4)3 + 6H2O + 5MnO2
Aluminium Sulphate and potassium hydroxide. Al2(SO4)3 + 6KOH = 3K2(SO4) + 2Al(OH)3
The balanced neutralization reaction between phosphorus acid (H3PO3) and aluminum hydroxide (Al(OH)3) produces aluminum phosphate (AlPO4) and water (H2O). The balanced chemical equation is: 2H3PO3 + 3Al(OH)3 → 2AlPO4 + 6H2O
The balanced equation for the reaction between aluminum hydroxide (Al(OH)3) and hydrochloric acid (HCl) in the stomach is: Al(OH)3 + 3HCl → AlCl3 + 3H2O This reaction forms aluminum chloride (AlCl3) and water (H2O).
The balanced chemical equation for the reaction between acetic acid (CH3COOH) and aluminum hydroxide (Al(OH)3) to form water and aluminum acetate (Al(CH3COO)3) is: 2CH3COOH + 3Al(OH)3 -> 3H2O + Al(CH3COO)3
(*Warning!!Xb42 is a atomic chemical,so do not mix aluminum oxide and dilute potassium hydroxide!!*)
To find the grams of aluminum hydroxide from 15.7 grams of aluminum sulfide, you first need to balance the chemical equation. The balanced equation is 2Al2S3 + 6H2O -> 4Al(OH)3 + 3H2S. Next, calculate the molar mass of aluminum sulfide (Al2S3) and aluminum hydroxide (Al(OH)3), then use the stoichiometry from the balanced equation to find the grams of aluminum hydroxide produced.
Aluminium Sulphate and potassium hydroxide. Al2(SO4)3 + 6KOH = 3K2(SO4) + 2Al(OH)3
Al(NO3)3 + 3 NaOH --> Al(OH)3 + 3 NaNO3
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
The balanced neutralization reaction between phosphorus acid (H3PO3) and aluminum hydroxide (Al(OH)3) produces aluminum phosphate (AlPO4) and water (H2O). The balanced chemical equation is: 2H3PO3 + 3Al(OH)3 → 2AlPO4 + 6H2O
The balanced chemical equation for the reaction between sodium hydroxide (NaOH) and aluminum sulfate (Al2(SO4)3) is: 6 NaOH + Al2(SO4)3 -> 3 Na2SO4 + 2 Al(OH)3 This reaction forms sodium sulfate and aluminum hydroxide.
The balanced equation for the reaction between aluminum hydroxide (Al(OH)3) and hydrochloric acid (HCl) in the stomach is: Al(OH)3 + 3HCl → AlCl3 + 3H2O This reaction forms aluminum chloride (AlCl3) and water (H2O).
Al2S3(s) + 6H2O(l) --> 2Al(OH)3(s) + 3H2S(g).
The balanced chemical equation for the reaction between acetic acid (CH3COOH) and aluminum hydroxide (Al(OH)3) to form water and aluminum acetate (Al(CH3COO)3) is: 2CH3COOH + 3Al(OH)3 -> 3H2O + Al(CH3COO)3
(*Warning!!Xb42 is a atomic chemical,so do not mix aluminum oxide and dilute potassium hydroxide!!*)
the balanced equation for ammonium hydroxide and perchloric acid is given below.NH4OH (aq) + HCl (aq) ---> NH4Cl (aq)+ H2O (l) .Above is the balanced molecular Equation.
The word eq'n is:- Hydrochloric Acid + Aluminium hydroxide = Aluminium Chloride + Water. Here is the BALANCED reaction eq'n 3HCl(aq) + Al(OH)3(aq) = AlCl3(aq) + 3H2O(l)