2Na + I2 ==> 2NaI
Sodium Iodide. Here is the balanced reaction eq'm 2Na(s) + I2(s) = 2NaI(s)
The balanced equation for fluorine reacting with sodium iodide is: 2 NaI + F2 → 2 NaF + I2
Solid sodium iodide reacts with water to form sodium ions and iodide ions. No further reactions occur because this compound is a salt of a strong acid and a strong base. Thus, the overall reaction is NaI(s)=> Na+ + I-
The ionic compound of sodium iodide is NaI. It is composed of sodium (Na+) ions and iodide (I-) ions held together by ionic bonds.
When sodium iodide is combined with chlorine, sodium chloride and iodine are produced as the products of the reaction. The balanced equation is: 2NaI + Cl2 → 2NaCl + I2.
Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq) Aqueous lead II nitrate reacts with aqueous sodium iodide to form solid lead II iodide precipitate and aqueous sodium nitrate.
The IUPAC name for sodium iodide is sodium iodide.
The balanced equation for the reaction between sodium (Na) and hydrogen iodide (HI) is: [ 2 \text{Na} + 2 \text{HI} \rightarrow 2 \text{NaI} + \text{H}_2 ] In this reaction, sodium displaces hydrogen from hydrogen iodide, producing sodium iodide (NaI) and hydrogen gas (H₂).
Sodium iodide
The chemical equation is: Na+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + Na+[NO3]- (aq)
The formula for sodium iodide is NaI. It is formed by the combination of sodium (Na) and iodide (I-) ions, with sodium donating an electron to iodine to form a stable compound.
Sodium iodide is a compound and that is its name.