the balanced symbol equation for nitric acid and sodium hydroxideis as follows :
potassium hydroxide + nitric acid → potassium nitrate + water.
KOH + HNO3 → KNO3 + H2O
HNO3 + NaOH = NaNO3 + H2O
Nitric acid: HNO3 (acid) Sodium hydroxide: NaOH (base) This is therefore an acid-base reaction. Acid + Base --> Salt + Water Therefore: HNO3 + NaOH --> NaNO3 + H20 Or: Nitric acid + Sodium hydroxide --> Sodium Nitrate + Water
This equation is NaHCO3 + HNO3 => NaNO3 + H2O + CO2 (g).
HCl + NaOH --> NaCl + H2O
There is no reaction , because of the Common Ion Effect. The Common Ion is the Hydroxide.
Sodium hydroxide does not react with hydrogen gas.
Nitric acid: HNO3 (acid) Sodium hydroxide: NaOH (base) This is therefore an acid-base reaction. Acid + Base --> Salt + Water Therefore: HNO3 + NaOH --> NaNO3 + H20 Or: Nitric acid + Sodium hydroxide --> Sodium Nitrate + Water
2Zn3O2
This equation is NaHCO3 + HNO3 => NaNO3 + H2O + CO2 (g).
HCl + NaOH --> NaCl + H2O
Na2O+H2O--->2NaOH
There is no reaction , because of the Common Ion Effect. The Common Ion is the Hydroxide.
Sodium hydroxide does not react with hydrogen gas.
NaOH + HCl >> NaCl + H2O
2Na + 2H2O -> 2NaOH + H2
2Na + 2H2O = 2NaOH + H2
The products will be sodium nitrate and water.Chemical equation: NaOH + HNO3 = NaNO3 + H2O
It doesn't need balancing - it's already balanced. NaHCO3 + NaOH → Na2CO3 + H2O