the balanced symbol equation for nitric acid and sodium hydroxideis as follows :
potassium hydroxide + nitric acid → potassium nitrate + water.
KOH + HNO3 → KNO3 + H2O
Nitric acid: HNO3 (acid) Sodium hydroxide: NaOH (base) This is therefore an acid-base reaction. Acid + Base --> Salt + Water Therefore: HNO3 + NaOH --> NaNO3 + H20 Or: Nitric acid + Sodium hydroxide --> Sodium Nitrate + Water
HNO3 (aq) + NaOH (aq) --> H2O (l) + NaNO3 (aq)
balance equation of sodium hydroxide and hydrochloric acid
There is no reaction between zinc hydroxide and sodium hydroxide.
sodium hydroxide and nitric acid is sodium nitrate and water
When sodium hydroxide (NaOH) is dissolved in water, it produces sodium and hydroxide ions. NaOH(aq) → Na+ +OH-
Nothing happens, so everything is balanced
NaCl and NaOH doesn't react.
I think it makes a sodium and lithium compound
Cl2 + 2NaOH ----- NaCl + NaOCl + H2O now this is a balanced chemical equation
Normal word equation: Aluminium (s) + sodium hydroxide (?) ----> aluminum hydroxide (aq) + sodium (s) Normal equation: Al + NaOH -----> AlOH + Na Balanced equation: Al + NaOH ------> AlOH + Na
This equation is NaHCO3 + HNO3 => NaNO3 + H2O + CO2 (g).
HCl + NaOH --> NaCl + H2O
when nitric acid reacts with sodium hydroxide it results to the formation of sodium nitrate and water
Sodium + water --> sodium hydroxide + hydrogen Symbol equation (balanced): 2Na(s) + 2H2O(l) --> 2NaOH(s) + H2(g)
MgSO4 + 2NaOH ---> Mg(OH)2 + Na2SO4 (magnesium hydroxide and sodium sulfate)
Sodium hydroxide+nitric acid ->sdium nitrate + water
The balanced equation for the saponification of glyceryl tristearate with aqueous sodium hydroxide is Carbon Hydrogen 3 Carbon Hydrogen 2 16 Carbon Oxygen.
Na2O + 2HNO3 ----------> 2NaNO3 + H2O
HC2H3O2 + NaOH → NaC2H3O2 + H2O Acetic acid + sodium hydroxide → sodium acetate + water
HCL + NaOH = NaCl + H2O
KHC8H4O4+ NaOH--->KNaC8H4O4+ H2O
NaOH + HCl >> NaCl + H2O