Cu(OH)2 => CuO + H2O.
The balanced equation for the decomposition of copper (II) hydroxide is: Cu(OH)2(s) → CuO(s) + H2O(g)
The balanced equation for the reaction between copper(II) hydroxide (Cu(OH)2) and sulfuric acid (H2SO4) is Cu(OH)2 + H2SO4 → CuSO4 + 2H2O.
copper bromide + sodium Hydroxide = Copper Hydroxide + Sodium Bromide CuBr2 + 2NaOH = Cu (OH)2 + 2NaBr
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
Copper(II) hydroxide, when heated, decomposes to form copper(II) oxide and water. The balanced equation for this reaction is: 2Cu(OH)2(s) -> 2CuO(s) + H2O(g)
CuSO₄+2NaOH=Na₂SO₄+Cu(OH)₂↓
2 NaOH + CuCl2 --> 2 NaCl + Cu(OH)2 (s)
The balanced equation is Cu(OH)2 (s) (heat) = CuO + H2O.
The balanced equation for the decomposition of copper carbonate hydroxide hydrate is: Cu2(OH)2CO3 (s) → CuO (s) + CO2 (g) + H2O (g). This reaction shows the breakdown of copper carbonate hydroxide hydrate into copper oxide, carbon dioxide, and water.
In the balanced equation CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4, copper sulfate (CuSO4) is a reactant. It reacts with sodium hydroxide (NaOH) to form copper hydroxide (Cu(OH)2) and sodium sulphate (Na2SO4).
When copper chloride is mixed with sodium hydroxide, a precipitation reaction occurs where solid copper(II) hydroxide is formed. The balanced chemical equation for this reaction is: CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl. This reaction is a double displacement reaction where copper ions and hydroxide ions switch partners to form the solid copper hydroxide.
The balanced chemical equation for the reaction between copper hydroxide (Cu(OH)2) and sulfuric acid (H2SO4) is: Cu(OH)2 + H2SO4 → CuSO4 + 2H2O