O-F is stronger than O-S
S-O
Polar Covalent.
Covalent bonds. The molecule ghas a bent shape with an O-S-O angle of near 120 0 and a rather short S-O bond length suggesting double bonds. Conventionally it is described as O=S=O
covalent
O-F is stronger than O-S
S-O
Yes. O::S::O (::=double bond)
Polar Covalent.
Covalent bonds. The molecule ghas a bent shape with an O-S-O angle of near 120 0 and a rather short S-O bond length suggesting double bonds. Conventionally it is described as O=S=O
covalent
It's a bond between a sulfur atom, and a carbonyl carbon:R-S-(C=O)-R
The structure of SO2 is a hybrid made up from two resonance structures. The sulfur is the central atom, with one oxygen on each side in a linear formation. The two resonance structures have one double bond between the Sulfur and an Oxygen and the other bond as a single bond. ( O=S-O or O-S=O) In reality, the actual structure is a hybrid, in which the electrons that form the double bond move freely between each oxygen. The best way to show this is to write the structure with two single bonds, and add a dashed line above each of the double bonds. (O-S-O with dashed above). Each bond can be considered 1.5 in magnitude.
If it is a double bond: Yes!, e.g. in H2C=O (formaldehyde, methanal)But in a single bond: No!, e.g. in H3C-O-H (methanol): Single bonds are sigma!
it would look like O-S-O and would be a polar-covalent bond and bent in structure
No, it's a molecular covalent bond.
No. O-H bond energy is larger