This would be a fairly simple experiment to do. You place your water in a chamber which is pressurized (or de-pressurized) to the desired degree of pressure, then slowly heat it with a Bunsen burner until it starts to boil; a thermomenter in the water will then tell you the temperature.
If you just want the information, and don't want to do the experiment yourself, information about the boiling and freezing point of water at all different temperatures and pressures is given in what is known as a phase diagram. This can be found by way of Google under "water phase diagram" or in the Handbook of Physics and Chemistry.
Water boils at 100 degrees Celsius at 760 mmHg. By using the Clausius-Clapeyron equation and plugging in the known variables (To = 100, Tb = 81, Po = 760, Hvap = 40.68 kJ/mol), the answer is derived to be approximately 376 mmHg.
I assume that you are referring to the "normal" boiling point, i.e. the temperature at which a substance boils at either 1 ATM or 1 bar. Hvap (enthalpy of vaporization) can be found at different condition than the another temperature by the following method:
1) Use the heat capacity of the liquid to find the energy involved in taking the liquid from the temperature of interest to the boiling point temperature. If you have a formula then you have to integrate from the starting temperature to the boiling point temperature. If you have a constant (which is just a rough approximation of the average heat capacity over a range of temperatures) then just use
H = Cp(liquid)(Tboiling-Tinitial).
2) Add the heat of vaporization at the boiling point (Hvap)
3) Finally, add the enthalpy change for taking the vapor from the boiling point to the condition of interest. For an ideal gas, this would just be H = Cp(gas)(Tboiling-Tfinal). For real gases it is a little more complicated as you have to integrate PV over the change in pressure from 1 ATM (or 1 bar) to the final pressure. For an ideal gas, PV is constant so the integral is zero, but for real gasses with substantial pressure changes, the integral can be non-zero.
We can find the boiling point using the clausius clayperon equation .
You cannot. There is no simple relationship between the two.
For water it is 100 degrees celsius, however it is different for other liquids ------------------------- Generally, boiling point is the temperature at which the liquid's vapour pressure is equal to the external atmospheric pressure.
At the same atmospheric pressure, yes. That's kind of the definition of boiling point: when the vapor pressure is the same as the atmospheric pressure.
its boiling
The boiling point of water is dependent on the atmospheric pressure. If you increase the pressure - for example, in a pressure cooker - the boiling point can be raised considerably. At high altitudes, the boiling point is significantly lower. At sea level, pure water boils at 212 degrees Fahrenheit which is the same as 100 degrees Celsius.
Higher altitude decreases the boiling point of water. Boiling point is defined as the point at which the vapour pressure of the substance above the liquid is equal to the external atmospheric pressure. Since the external atmospheric pressure is lower at higher altitudes, a lower vapour pressure of water is required for water to boil and therefore a lower temperature is required to achieve the desired vapour pressure.
In atmospheric pressure (ie at sea level), water boils at 100 degrees Celsius.
373 kelvin 100 celsius kelvin is basically celsius + 273
It is a relating to a temperature scale that registers the freezing point of water as 0° Celsius and the boiling point as 100° Celsius under normal atmospheric pressure.
212 Fahrenheit It is the boiling temperature of pure water under one atmospheric pressure
The water boiling point in Celsius is 100 °C.
The normal boiling point(also called the atmospheric boiling point or the atmospheric pressure boiling point)is the temperature at which the vapor pressure of a liquid equals the atmospheric pressure at sea level, 1 atmosphere.The normal boiling point of water is about 100 degrees Celsius at a pressure of 1 ATM (i.e., 101.325 kPa).General Useful Information:The boiling point of a liquid is the temperature at which the vapor pressure of the liquid equals the environmental pressure, but the environmental pressure may or may not be equal to the atmospheric pressure at sea level, 1 ATM.If the surrounding environmental pressure is less than atmospheric pressure, then the boiling point is less than the normal boiling point.If the surrounding environmental pressure is greater than atmospheric pressure, then the boiling point is greater than the normal boiling point.At the boiling point, adding enough heat to the liquid will cause the liquid to vaporize (that is boil or form a gas).
glycerin is distilled at reduced pressure because it has boiling point of 290 degree celsius under atmospheric pressure it slightly decomposes but under reduced pressure it distills unchanged
The normal boiling point (also called the atmospheric boiling point or the atmospheric pressure boiling point) of a liquid is the special case in which the vapor pressure of the liquid equals the defined atmospheric pressure at sea level, atmosphere
For water it is 100 degrees celsius, however it is different for other liquids ------------------------- Generally, boiling point is the temperature at which the liquid's vapour pressure is equal to the external atmospheric pressure.
Zero freezing point and 100 degrees boiling point is on the Celsius Scale.
The boiling point of acetone is approximately 56 degrees Celsius or 132 degrees Fahrenheit at standard atmospheric pressure.
They are the boiling point of pure water at normal atmospheric pressure.