Want this question answered?
The answer will be 5 m/sec/sec 300m/sec - 200m/sec divided by 20 seconds will get you 100m/sec divided by 20 seconds, which then equals 5
The car's uniform acceleration is (change in speed) divided by (change in time) = (24 m/s) / (2.95 s) = 8.1356 meters/sec2. Call this number ' A ' for acceleration. Change in speed = ( A ) times (time) Time = (change in speed) / A = (20 - 10) / A = 10/A = 0.81356 seconds (rounded)
Acceleration = (change in speed) divided by (time for the change) = (9/3) = 3 m/s2
If you assume that the initial speed is zero, you can calculate the distance using the formula:distance = 1/2 x acceleration x time squared
Average speed = (250 / 5) = 50 meters per second.Initial speed = 0Final speed = 100 m/sAcceleration = (100 / 5) = 20 m/s2===> Must be a rocket-propelled ball; its acceleration is 2G !
Acceleration = change in speed/time = (20-5)/3 = 15/3 = 5 units of speed per second. It is not possible to be any more precise because the unit of speed (kilometres per hour, miles per hour, metres per second) is unspecified.
The answer will be 5 m/sec/sec 300m/sec - 200m/sec divided by 20 seconds will get you 100m/sec divided by 20 seconds, which then equals 5
Acceleration = Change in speed/Time Time = Change in Speed/Acceleration = 65mph/20mph per s = 65/20 seconds = 3.25 seconds
3 ms-2
The formula for finding time based on acceleration and speed is: (Delta)t = (Delta)v/a Change in time = change in speed / acceleration t = 75-15 / 20 t = 60 / 20 t = 3 seconds
20 MPH would be colder, as the increased speed increased heat transfer away from the moving object.
-- "Acceleration" is any change of velocity.-- "Velocity" is a speed and its direction.-- "20 meters per second" is a speed, not a velocity, because it doesn't mention a direction.-- We don't have enough information to say anything about that car's acceleration.If, for example, it happens to be moving at a constant speed of 20 meters per secondon a circular track, then it has plenty of acceleration.
The car's uniform acceleration is (change in speed) divided by (change in time) = (24 m/s) / (2.95 s) = 8.1356 meters/sec2. Call this number ' A ' for acceleration. Change in speed = ( A ) times (time) Time = (change in speed) / A = (20 - 10) / A = 10/A = 0.81356 seconds (rounded)
5 m/s2 east
well we know that we have two speeds and a time. So, initial speed = 80 final speed = 60 change in time = 6 Now acceleration in this case will be measured in kilometers per hour per second (i.e. every x seconds, y kilometers per hour are gained in speed) So we simply apply the formula Acceleration = (final speed - initial speed)/ change in time = (80 - 60)/6 = 20/6 = 3.6666667 km/h/s
Magnituide of acceleration = (change in speed) divided by (time for the change)= (final speed - initial speed) divided by (time for the change)= 2/20 = 0.1 meter per second2Note that this is the magnitude of the acceleration, obtained by working with the speeds.We don't know the initial or final velocities, because there's no information regarding directions.Similarly, we only know the magnitude of the acceleration, not its direction.
Acceleration = rate of change of speed = (change of speed) / (time interval) = (25 - 5) / 4 = 20/4 = 5 m/s2