If you assume that the initial speed is zero, you can calculate the distance using the formula:distance = 1/2 x acceleration x time squared
Assuming (1) the object starts from rest, (2) air resistance is insignificant, the object speeds up by about 9.8 meters/second every second. That's the strength of the gravitational field. Just multiply this acceleration (9.8 meters/second2) by the time.
You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.
Acceleration is a vector, meaning each acceleration has both magnitude and direction. The resultant of vectors is basically the net acceleration on the object expressed as a single vector. For example, if there are two vectors each with a magnitude of 2 meters/(seconds squared) acting on an object and these vectors were placed on the x and y axes then you could represent this system of 2 vectors 90 degrees apart each with a magnitude of two meters/(seconds squared) as one vector of 45 degrees with a magnitude of 2 times the square root of 2 meters/(seconds squared).
Acceleration is a vector, meaning each acceleration has both magnitude and direction. The resultant of vectors is basically the net acceleration on the object expressed as a single vector. For example, if there are two vectors each with a magnitude of 2 meters/(seconds squared) acting on an object and these vectors were placed on the x and y axes then you could represent this system of 2 vectors 90 degrees apart each with a magnitude of two meters/(seconds squared) as one vector of 45 degrees with a magnitude of 2 times the square root of 2 meters/(seconds squared).
Square seconds, by itself, doesn't make much sense. On the other hand, please note that acceleration is not the same as speed or velocity, therefore you would expect the units to be different between the two. Speed or velocity is measured in meters / second; since acceleration is the change of rate of a velocity (in symbols: dv/dt), its units are velocity / time. Using SI units, that would be (meters / second) / second, and this is commonly written as meters / second2, which makes sense since the seconds appear twice in the denominator.
If air resistance can be ignored, the distance in meters is 4.9t2. Note that 4.9 is half the numerical value of Earth's acceleration (9.8 meters per second square).
Assuming (1) the object starts from rest, (2) air resistance is insignificant, the object speeds up by about 9.8 meters/second every second. That's the strength of the gravitational field. Just multiply this acceleration (9.8 meters/second2) by the time.
"470 meters per second" is a speed, not an acceleration. Assuming you mean "470 meters per second square", that is the same as a change of 470 meters per second every second. Just multiply by the number of seconds to get the change in speed."470 meters per second" is a speed, not an acceleration. Assuming you mean "470 meters per second square", that is the same as a change of 470 meters per second every second. Just multiply by the number of seconds to get the change in speed."470 meters per second" is a speed, not an acceleration. Assuming you mean "470 meters per second square", that is the same as a change of 470 meters per second every second. Just multiply by the number of seconds to get the change in speed."470 meters per second" is a speed, not an acceleration. Assuming you mean "470 meters per second square", that is the same as a change of 470 meters per second every second. Just multiply by the number of seconds to get the change in speed.
You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.You divide the given acceleration by the standard acceleration due to Earth's gravity. If the acceleration is in meters per second square, you divide by 9.8.
Kilometers per hour is used to measure speed, not acceleration. In SI, the acceleration is commonly measured in meters per square second.Kilometers per hour is used to measure speed, not acceleration. In SI, the acceleration is commonly measured in meters per square second.Kilometers per hour is used to measure speed, not acceleration. In SI, the acceleration is commonly measured in meters per square second.Kilometers per hour is used to measure speed, not acceleration. In SI, the acceleration is commonly measured in meters per square second.
Initially 9.8 meters per second square. Later, as air resistance increases, the acceleration will be less and less.Initially 9.8 meters per second square. Later, as air resistance increases, the acceleration will be less and less.Initially 9.8 meters per second square. Later, as air resistance increases, the acceleration will be less and less.Initially 9.8 meters per second square. Later, as air resistance increases, the acceleration will be less and less.
Acceleration is a vector, meaning each acceleration has both magnitude and direction. The resultant of vectors is basically the net acceleration on the object expressed as a single vector. For example, if there are two vectors each with a magnitude of 2 meters/(seconds squared) acting on an object and these vectors were placed on the x and y axes then you could represent this system of 2 vectors 90 degrees apart each with a magnitude of two meters/(seconds squared) as one vector of 45 degrees with a magnitude of 2 times the square root of 2 meters/(seconds squared).
Acceleration is a vector, meaning each acceleration has both magnitude and direction. The resultant of vectors is basically the net acceleration on the object expressed as a single vector. For example, if there are two vectors each with a magnitude of 2 meters/(seconds squared) acting on an object and these vectors were placed on the x and y axes then you could represent this system of 2 vectors 90 degrees apart each with a magnitude of two meters/(seconds squared) as one vector of 45 degrees with a magnitude of 2 times the square root of 2 meters/(seconds squared).
Acceleration is a vector, meaning each acceleration has both magnitude and direction. The resultant of vectors is basically the net acceleration on the object expressed as a single vector. For example, if there are two vectors each with a magnitude of 2 meters/(seconds squared) acting on an object and these vectors were placed on the x and y axes then you could represent this system of 2 vectors 90 degrees apart each with a magnitude of two meters/(seconds squared) as one vector of 45 degrees with a magnitude of 2 times the square root of 2 meters/(seconds squared).
The acceleration is expressed in meters per second square, which really means (meters / second) / second. Every second, the skydiver will be 10 meters per second faster than the previous second. Therefore, after 3 seconds, he will have a speed of 30 meters per second.
Square seconds, by itself, doesn't make much sense. On the other hand, please note that acceleration is not the same as speed or velocity, therefore you would expect the units to be different between the two. Speed or velocity is measured in meters / second; since acceleration is the change of rate of a velocity (in symbols: dv/dt), its units are velocity / time. Using SI units, that would be (meters / second) / second, and this is commonly written as meters / second2, which makes sense since the seconds appear twice in the denominator.
36 meters is not a "rate".If you have an acceleration (in meters per second square), use Newton's Second Law:Net force = mass x acceleration.36 meters is not a "rate".If you have an acceleration (in meters per second square), use Newton's Second Law:Net force = mass x acceleration.36 meters is not a "rate".If you have an acceleration (in meters per second square), use Newton's Second Law:Net force = mass x acceleration.36 meters is not a "rate".If you have an acceleration (in meters per second square), use Newton's Second Law:Net force = mass x acceleration.