Since Oxygen has an ion charge of -2 & Copper has a 2 as a subscript, it means that Copper's ion charge will be +1.
Cu2O = Copper (I) Oxide
The charge of both copper (Cu) and oxygen (O) are both 2.
copper sulfate is an ionic compound whose overall charge is zero. The copper ions have a +2 charge. The sulfate ions have a -2 charge.
negative
hellooo
Copper(2)oxide is written as Cu2O.Not that the last alphabet is O for oxygen,not 0 for zero Actually Copper (II) Oxide is written as CuO, because Copper 2 has the charge 2+ and Oxygen has the charge 2-, so they balance each other out evenly. THere is no need for 2 (Cu2)'s.
Copper(II) oxide: CuO
12.5 (g CuCO3) = [12.5 (g CuCO3) / 123.555 (g/mol CuCO3)] = 0.1012 (mol CuCO3)0.1012 (mol CuCO3)* [1 (mol CuO) / (mol CuCO3)] = 0.1012 (mol CuO)= [0.1012 (mol CuO) * 79.545 (g/mol CuO)] = 8.047 g CuO = 8.05 g CuO
2 Fe + 3 CuO -> Fe2O3 + 3 Cu
As there are two of them, the charge on the copper ion is 1+ to balance the charge of the oxygen (2-).
hellooo
In CuO, as oxygen is he most electronegative among the non metals.
1 mole CuO = 79.5454g CuO 3.2g CuO x 1mol CuO/79.5454g CuO = 0.040 mole CuO
Copper(2)oxide is written as Cu2O.Not that the last alphabet is O for oxygen,not 0 for zero Actually Copper (II) Oxide is written as CuO, because Copper 2 has the charge 2+ and Oxygen has the charge 2-, so they balance each other out evenly. THere is no need for 2 (Cu2)'s.
Copper(II) oxide: CuO
You sha cuo mao ai cuo - 1999 is rated/received certificates of: Hong Kong:IIB
Copper (II) oxide is the name for CuO.
12.5 (g CuCO3) = [12.5 (g CuCO3) / 123.555 (g/mol CuCO3)] = 0.1012 (mol CuCO3)0.1012 (mol CuCO3)* [1 (mol CuO) / (mol CuCO3)] = 0.1012 (mol CuO)= [0.1012 (mol CuO) * 79.545 (g/mol CuO)] = 8.047 g CuO = 8.05 g CuO
CuO is made up of Cu2+ and O2- ions. So there are two ions, per molecule of CuO.
CuO and CO2 (as a dry gas) has not a pH.
CuO is a compound. It is not a mixture.