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What mass of CuO will be obatined by heating 12.5gm of copper carbonate?
Updated: 11/4/2022
Wiki User
∙ 11y agoBest Answer
12.5 (g CuCO3) = [12.5 (g CuCO3) / 123.555 (g/mol CuCO3)] = 0.1012 (mol CuCO3)
0.1012 (mol CuCO3)* [1 (mol CuO) / (mol CuCO3)] = 0.1012 (mol CuO)
= [0.1012 (mol CuO) * 79.545 (g/mol CuO)] = 8.047 g CuO = 8.05 g CuO
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∙ 11y agoThis answer is:
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