1 mole CuO = 79.5454g CuO
3.2g CuO x 1mol CuO/79.5454g CuO = 0.040 mole CuO
The balanced chemical equation for the reaction between CuO and HCl is: CuO + 2HCl --> CuCl2 + H2O This equation shows that 1 mole of CuO reacts with 2 moles of HCl. Therefore, to react with 4 moles of HCl, you would need 2 moles of CuO.
4 mole cuO X 2/1 = 8 mole Hcl
We need to go from grams of CuO to mL of H2SO4. Atomic weight of CuO = 63.55 g Cu + 16 g O = 79.55 g CuO (.80 g CuO) * (1 mol CuO / 79.55 g CuO) = .0100566 mol CuO (g CuO cancel) Since the moles of CuO is a 1:1 ratio to H2SO4 (see balanced equation) we know that: mol CuO = mol H2SO4 or 0.0100566 mol CuO = 0.0100566 mol H2SO4 3.0 M of H2SO4 means that there is 3 mol / 1 L. So we can divide this by the moles to get L then mL of H2SO4 (0.0100566 mol H2SO4) * (1 L H2SO4 / 3 mol H2SO4) * (1000 mL H2SO4 / 1 L H2SO4) = 3.4 mL H2SO4 (mol H2SO4 and L H2SO4 cancel) So 3.4 ml of H2SO4 is needed to react with 0.80 g of CuO.
To find the mass of 0.125 moles of copper (II) oxide (CuO), you need to determine the molar mass of CuO which is 79.55 g/mol. Multiply the molar mass by the number of moles to get the mass. Therefore, 0.125 moles of CuO would have a mass of 9.94 grams.
To determine the mass of CuO formed, first calculate the moles of each reactant using their molar masses. Then, determine the limiting reactant by comparing the moles of CuO that could be formed from each reactant. Finally, use the limiting reactant to calculate the mass of CuO formed based on the balanced chemical equation.
The balanced chemical equation for the reaction between CuO and HCl is: CuO + 2HCl --> CuCl2 + H2O This equation shows that 1 mole of CuO reacts with 2 moles of HCl. Therefore, to react with 4 moles of HCl, you would need 2 moles of CuO.
4 mole cuO X 2/1 = 8 mole Hcl
79.5 g of CuO = 1 g So, 3.2 g = (1*3.2) / 79.5 = 0.04 mole
We need to go from grams of CuO to mL of H2SO4. Atomic weight of CuO = 63.55 g Cu + 16 g O = 79.55 g CuO (.80 g CuO) * (1 mol CuO / 79.55 g CuO) = .0100566 mol CuO (g CuO cancel) Since the moles of CuO is a 1:1 ratio to H2SO4 (see balanced equation) we know that: mol CuO = mol H2SO4 or 0.0100566 mol CuO = 0.0100566 mol H2SO4 3.0 M of H2SO4 means that there is 3 mol / 1 L. So we can divide this by the moles to get L then mL of H2SO4 (0.0100566 mol H2SO4) * (1 L H2SO4 / 3 mol H2SO4) * (1000 mL H2SO4 / 1 L H2SO4) = 3.4 mL H2SO4 (mol H2SO4 and L H2SO4 cancel) So 3.4 ml of H2SO4 is needed to react with 0.80 g of CuO.
11 g hydrogen are needed.
To find the mass of 0.125 moles of copper (II) oxide (CuO), you need to determine the molar mass of CuO which is 79.55 g/mol. Multiply the molar mass by the number of moles to get the mass. Therefore, 0.125 moles of CuO would have a mass of 9.94 grams.
The molar mass of Cu is 63.55 g/mol and of O is 16 g/mol. The moles of Cu used is 127g / 63.55 g/mol = 2 mol, and the moles of O used is 32g / 16 g/mol = 2 mol. Since the mole ratio of Cu to O in CuO is 1:1, then 2 mol of Cu will react with 2 mol of O to form 2 mol of CuO. The mass of 2 mol of CuO is 159.6g.
To determine the mass of CuO formed, first calculate the moles of each reactant using their molar masses. Then, determine the limiting reactant by comparing the moles of CuO that could be formed from each reactant. Finally, use the limiting reactant to calculate the mass of CuO formed based on the balanced chemical equation.
112/32 moles for every mole of sulfur there are 32g
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : mass = Mr x number of moles mass = 32g/mol x 50mols = 1600g
32g increased by 8% = 34.56g = 32g + (8% * 32g) = 32g + (0.08 * 32g) = 32g + 2.56g = 34.56g
Grams is a unit of weight, miles is a unit of distance. There's no comparison between the two.