answersLogoWhite

0


Best Answer

We need to go from grams of CuO to mL of H2SO4.

Atomic weight of CuO = 63.55 g Cu + 16 g O = 79.55 g CuO

(.80 g CuO) * (1 mol CuO / 79.55 g CuO) = .0100566 mol CuO (g CuO cancel)

Since the moles of CuO is a 1:1 ratio to H2SO4 (see balanced equation) we know that: mol CuO = mol H2SO4 or 0.0100566 mol CuO = 0.0100566 mol H2SO4

3.0 M of H2SO4 means that there is 3 mol / 1 L. So we can divide this by the moles to get L then mL of H2SO4

(0.0100566 mol H2SO4) * (1 L H2SO4 / 3 mol H2SO4) * (1000 mL H2SO4 / 1 L H2SO4) = 3.4 mL H2SO4 (mol H2SO4 and L H2SO4 cancel)

So 3.4 ml of H2SO4 is needed to react with 0.80 g of CuO.

User Avatar

Wiki User

13y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

14y ago

Doesn't matter. Stop using the internet for answers and figure it for yourself

This answer is:
User Avatar

User Avatar

Wiki User

6y ago

The volume of sulfuric acid is 2,3 mL.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many milliliters of 3.0 m h2so4 are required to react with 0.80 g of cuo in the equation cuo h2so4 cuso4 H2O?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions