No it isn't. It aquires properties from H2SO4 which is a strong acid, although cuso4 is a salt.
CuSO4 is a salt of weak base(copper hydroxide) and strong acid(sulphuric acid)....the Ph of the solution of cuso4 will be acidic....
HCl + CuSO4
CuSO4
CuSO4 is ionic.
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
CuSO4 is a salt of weak base(copper hydroxide) and strong acid(sulphuric acid)....the Ph of the solution of cuso4 will be acidic....
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
HCl + CuSO4
CuSO4 . 2H2O
CuSO4
CuSO4 is ionic.
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
CuSO4 is water soluble. CaCO3 is not.
CuSO4 is the chemical formula of copper(II) sulfate.
Zn + CuSO4 --> ZnSO4 + Cu
No. The % of Cu by mass in CuSO4 will be greater than the % of Cu by mass in the pentahydrate (5H2O) because in the hydrate there is added mass (5 H2O = 90 g) but no added Cu.
their isn't one CuSO4 is an anhydrous salt which will absorb water so the way to find out how much is in it is to find out the difference in water befor and after addition and calculate it by finding the mols of water absorbed incomplarison with the number of mols of CuSO4 used. it is normally wrighten nH2O. CuSO4