No it isn't. It aquires properties from H2SO4 which is a strong acid, although cuso4 is a salt.
CuSO4 is a salt of weak base(copper hydroxide) and strong acid(sulphuric acid)....the Ph of the solution of cuso4 will be acidic....
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
Yes, CuSO4 is an electrolyte.
No, the percent by mass of copper in CuSO4 5H2O will be different than in CuSO4 because CuSO4 5H2O includes water molecules in addition to the copper sulfate compound itself. Therefore, the total mass of CuSO4 5H2O will be greater, resulting in a lower percent by mass of copper in CuSO4 5H2O compared to CuSO4.
their isn't one CuSO4 is an anhydrous salt which will absorb water so the way to find out how much is in it is to find out the difference in water befor and after addition and calculate it by finding the mols of water absorbed incomplarison with the number of mols of CuSO4 used. it is normally wrighten nH2O. CuSO4
CuSO4 is a salt of weak base(copper hydroxide) and strong acid(sulphuric acid)....the Ph of the solution of cuso4 will be acidic....
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
Yes, CuSO4 is an electrolyte.
No, the percent by mass of copper in CuSO4 5H2O will be different than in CuSO4 because CuSO4 5H2O includes water molecules in addition to the copper sulfate compound itself. Therefore, the total mass of CuSO4 5H2O will be greater, resulting in a lower percent by mass of copper in CuSO4 5H2O compared to CuSO4.
their isn't one CuSO4 is an anhydrous salt which will absorb water so the way to find out how much is in it is to find out the difference in water befor and after addition and calculate it by finding the mols of water absorbed incomplarison with the number of mols of CuSO4 used. it is normally wrighten nH2O. CuSO4
The chemical equation for the reaction between hydrochloric acid (HCl) and copper (II) sulfate (CuSO4) is: 2 HCl + CuSO4 -> CuCl2 + H2SO4
CuSO4 · 5H2O has 5 water molecules attached to each CuSO4 molecule.
CuSO4•5H2O + heat ---> CuSO4 + 5H2O
The ratio of moles of CuSO4 to moles of water in CuSO4•5H2O is 1:5. This is because there is one mole of CuSO4 for every five moles of water in the compound.
Zn + CuSO4 --> ZnSO4 + Cu
CuSO4 is the chemical formula of copper(II) sulfate.