their isn't one
CuSO4 is an anhydrous salt which will absorb water so the way to find out how much is in it is to find out the difference in water befor and after addition and calculate it by finding the mols of water absorbed incomplarison with the number of mols of CuSO4 used.
it is normally wrighten nH2O. CuSO4
Hydrated Copper(11) Sulphate: CuSO4.5H2O(aq) --heat-->CuSO4+5H2O
CuSO4 * 5H2O + heat à CuSO4 + 5H2O
CuSO4•5H2O + heat ---> CuSO4 + 5H2O
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
There is a balanced equation to use for decomposition of copper II sulfate pentahydrate. It is the following: CuSO4.5H2O+heat -->CuSO4(anhydrous)+5H2O.
CuSO4 * 5H2O ----> CuSO4 + 5H2O. This is true because CuSO4 * 5 H2O is a salt weakly bounded to water, that is why it is hydrous. When it decomposes, the weak bonds are broken making the products above. CuSO4*5H2O formula is [Cu(OH2)4]SO4*H2O CuSO4 + 5H2O --> [Cu(OH2)4]SO4*H2O
C4H10 + 6.5O2 4CO2 + 5H2O + heat
CuSO4•5H2O + heat ---> CuSO4 + 5H2O
cuso4 - 5h2o= cuso4 + 5h20 + heat
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
29.8g H2O = 1.66 mol H2O Molar Mass CuSO4 * 5H2O = 249.6 g mol CuSO4 * 5H2O --> 5 mol H2O 249.6 g CuSO4 * 5H2O/1 mol CuSO4 * 5H2O Times * 1mol CuSO4 * 5H2O/5mol H2O Times* 1.66 mol H2O = 82.6 g CuSO4 * 5H2O
There is a balanced equation to use for decomposition of copper II sulfate pentahydrate. It is the following: CuSO4.5H2O+heat -->CuSO4(anhydrous)+5H2O.
CuSO4 * 5H2O ----> CuSO4 + 5H2O. This is true because CuSO4 * 5 H2O is a salt weakly bounded to water, that is why it is hydrous. When it decomposes, the weak bonds are broken making the products above. CuSO4*5H2O formula is [Cu(OH2)4]SO4*H2O CuSO4 + 5H2O --> [Cu(OH2)4]SO4*H2O
Copper sulfate in its solid crystal from present as pentahydrate (CuSO4 5 H2O). When heated strongly it loses water molecules and becomes CuSO4. Note that CuSO4 5 H2O is blue in color whereas CuSO4 is colourless since absorption region shifted from visible region. On further heating it is dissociated to CuO.
C4H10 + 6.5O2 4CO2 + 5H2O + heat
2C4H10 + 13O2 ==> 8CO2 + 10H2O complete combustion of isobutane
The chemical equation for the dehydration of magnesium sulfate (MgSO4) is as follows: MgSO4·7H2O + Heat => MgSO4 + 7H2O A link is provided below for more information.
It turns into blueish clear crystals but only if u don't have a lid on it when it is heated!add. as it is heated, the water of crystallization will be driven off, and soon you'll have a greenish powder.
dehydration