Sn (s) + 2HNO3(aq)-> H2O(l) + 2NO2(g)+SnO(s)
If the product formed is Tin (II) oxide, then the above should be the balanced equation. Tin (II) oxide can be blue black or red, depending upon the stability.
Lead oxide + nitric acid ---> lead nitrate + water 2HNO3 (aq) + PbO(s) ---> Pb(NO3)2 (aq) + H2O(l)
2Sn +O2 ------> 2SnO also because tin can be in oxidation state 4 the following is aslso valid Sn + O2 ----> SnO2
Zn(solid) + 2HNO3(liq) --> Zn2+(aq) + 2 NO3-(aq) + H2(gas)
Nitrate is (NO3) with a charge of 1-
Tin is (Sn) with a charge of 4+
Therefore, together, they are Sn(NO3)4
Zn + 4HNO3 --> Zn(NO3)2 + 2H2O + 2NO2
hot and conc.
submitted by Tirth
FTW
Tin nitrates are:
- Sn(II)(NO3)2
- Sn(IV)(NO3)4
2HBr(l)+2Sn(s)->2SnBr(s)+H2(g)
zinc + nitric acid --> zinc nitrate + water and hydrogen I think...
Nitric acid plus zinc oxideNitricoxide
In hot concentrated acid, nitric is an oxidizing acid: 3Zn + 8HNO3 → 3Zn(NO3)2 + 2NO + 4H2O But in cold, dilute solutions: Zn(s) + 2HNO3 (aq) → Zn(NO3)2 (aq) + H2 (g)
ZnCO3 + 2HNO3 ----> Zn(NO3)2 + H2O + CO2
Zinc Nitrate
zinc + nitric acid --> zinc nitrate + water and hydrogen I think...
Nitric acid plus zinc oxideNitricoxide
Zn + 2H+ ----> Zn2+ + H2
In hot concentrated acid, nitric is an oxidizing acid: 3Zn + 8HNO3 → 3Zn(NO3)2 + 2NO + 4H2O But in cold, dilute solutions: Zn(s) + 2HNO3 (aq) → Zn(NO3)2 (aq) + H2 (g)
2CH3COOH + Zn =(CH3COO)2Zn + H2
I guess it's Zinc Nitrate
ZnCO3 + 2HNO3 ----> Zn(NO3)2 + H2O + CO2
The chemical equation (with dilute acid) is:Zn + HNO3 = Zn(NO3)2 +NO +H2O.
Zinc Nitrate
Zinc nitrate is a white substance.
You can not. It is impossible. This would produce zinc chloride.
Smithsonite