Sn (s) + 2HNO3(aq)-> H2O(l) + 2NO2(g)+SnO(s)
If the product formed is Tin (II) oxide, then the above should be the balanced equation. Tin (II) oxide can be blue black or red, depending upon the stability.
zinc + nitric acid --> zinc nitrate + water and hydrogen I think...
Nitric acid plus zinc oxideNitricoxide
ZnCO3 + 2HNO3 ----> Zn(NO3)2 + H2O + CO2
In hot concentrated acid, nitric is an oxidizing acid: 3Zn + 8HNO3 → 3Zn(NO3)2 + 2NO + 4H2O But in cold, dilute solutions: Zn(s) + 2HNO3 (aq) → Zn(NO3)2 (aq) + H2 (g)
Zinc and Nitric acid react to produce Zinc nitrate, Water and Nitrogen Mono Oxide if the Nitric acid is Dilute... 3Zn + 8HNO3 = 3Zn[No3]2 + 4H20 + 2NO
zinc + nitric acid --> zinc nitrate + water and hydrogen I think...
Nitric acid plus zinc oxideNitricoxide
ZnCO3 + 2HNO3 ----> Zn(NO3)2 + H2O + CO2
In hot concentrated acid, nitric is an oxidizing acid: 3Zn + 8HNO3 → 3Zn(NO3)2 + 2NO + 4H2O But in cold, dilute solutions: Zn(s) + 2HNO3 (aq) → Zn(NO3)2 (aq) + H2 (g)
Zinc and Nitric acid react to produce Zinc nitrate, Water and Nitrogen Mono Oxide if the Nitric acid is Dilute... 3Zn + 8HNO3 = 3Zn[No3]2 + 4H20 + 2NO
The products are zinc nitrate and water. ZnO + 2HNO3 --> Zn(NO3)2 + H2O
Zn + 2H+ ----> Zn2+ + H2
Zn + H2SO4 → ZnSO4 + H2
The equation is: Zn + 2HNO3 -----> Zn(NO3)2 + H2
The balanced equation for the reaction between zinc and hydrochloric acid (HCl) is: Zn + 2HCl -> ZnCl2 + H2.
The word equation for the reaction between magnesium and nitric acid is: magnesium + nitric acid → magnesium nitrate + hydrogen. In this reaction, magnesium reacts with nitric acid to form magnesium nitrate and hydrogen gas. The balanced chemical equation for this reaction is: 3Mg + 8HNO3 → 3Mg(NO3)2 + 2NO + 4H2O.
The balanced equation for the reaction between zinc oxide (ZnO) and hydrochloric acid (HCl) is: ZnO + 2HCl → ZnCl2 + H2O