Volts x Amps = Watts, divide with 1000 and you get kilowatts.
Wire sizing is determined by the amount of amperage that the connected device draws. Look on the nameplate of the motor and state the amperage. Then the question can be answered.
415 V is the 'line voltage', and 240 V is the 'phase voltage' of a 415/240-V three-phase, four-wire, system. These were the standard nominal voltages used in the UK before EU 'harmonisation' forced them to be 'renamed' (but not actually changed) to '400/230 V'!! So there really isn't such a thing as separate '415-V' and '240-V' three-phase systems. And there is no economic way of changing the supply frequency to a different frequency. Incidentally, the symbol for 'hertz' is 'Hz', not 'htz'.
100 KW divided by 415 volts is 241 amperes. Power = voltage times current, so current = power divided by voltage.
we can use the formula: Ip=KW/3/volts/pf
Power = voltage times current, and the power loss is the loss in the line, I^2 * R. At 11,000 volts, the current will be (11,000 / 415 = ) 3.77% of what it is at 415 volts. So the power loss in the line at 11,000 volts will be (3.77% ^2 = ) .14% of what it is at 415 volts.
Look on the equipment near where the electrical cable enters, and there should be a small plate with the correct voltage range printed on it.
The answer is 40,000 divided by 415 or 96.38 Amps. Watts is volts times amps.
415 volts
That would depend on the power output (watts) of the circuit. Volts times the Amperage equals the Wattage of the circuit. You do not have enough information in your question. Volts is the force applied to move the electrons in the circuit, and amps are a measure of the quantity of electrons moved through the circuit over time. Thus a circuit of 415 volts and 1 ampere will deliver 415 watt-hours of power. Yet a circuit of 1 volt at 415 amps will deliver the same 415 watt-hours of power, but with less force.
Volts x Amps = Watts, divide with 1000 and you get kilowatts.
I Can Not answer. It is my question.
The cable size depends on a few factors, such as the supply voltage, the method of starting the motor, (direct-on-line, or star delta) and the length of cable required to compensate for voltage drop. Also, if the cable is copper or aluminum.110 kW motor has a rated current of 200 amps at 415 volts, so the correct copper cable size would have a cross-sectional area of 75 square mm., if the motor is started direct-on-line.At 660 volts, the rated current would be 118 volts and the cable size would be 35 square mm.
Wire sizing is determined by the amount of amperage that the connected device draws. Look on the nameplate of the motor and state the amperage. Then the question can be answered.
When cable reference is made about voltage it is the cables insulation factor that comes into play. Cables in North America have common voltage ratings of 300, 600 and 1000 volts. A cable capable of handling 240 volts will have a rating of 300 volts. The ratings of each specific cable is printed on the cable's outer jacket.
Brown black and ground (yellow=green). The brown and black can alco be black and blue and brown and black
It depends on the cable. 0 to 5000 volts the minimum bending radius is 6 x diameter of the cable. Above 5000 volts the minimum bending radius is 8 x the diameter of the cable.