The oxidation number of hydrogen in KH is -1, because the only oxidation number for potassium in a simple inorganic compound is +1. A hydrogen atom can complete its outer electron shell by adding one electron acquire the electron configuration of helium, and this is what happens during the formation of alkali metal hydrides such as KH.
The oxidation number of hydrogen in potassium hydride is -1, because hydrogen has a much higher electronegativity than potassium, even though in most of its compounds hydrogen is more likely to have an oxidation number of +1.
It largely depend on what H is bonded with. Usually, its +1, however, in the case of metal hydrides, it would be -1.
with a -1 oxidation it is Hydride ion H1-
Pottasium has plus 1 state.It is common to every compound.
It has three Oxidation numbers.They are +!,-1 and zero.
The Potassium (K) has an oxidation number of +1. The Bromine (Br) has an oxidation number of -1.
KCLO3 the oxidation number of potassuim is +1, oxidation number of chlorine is +5 the oxidation number of oxygen is -2 and there are 3 atoms of oxygen KClO3=1+5+(-2)3=0 therefore the oxidation number of KClO3 =0 or neutral
+1 for K -2 for each O +5 for N
K has an oxidation number of +1 O has an oxidation number of (-2) x 4 So... the oxidation number for Mn is whatever is needed to make 1-8 equal to zero. Therefore, the oxidation number for Mn is +7
the oxidation number of each K is +1. But there are two K's so 1*2 is +2. the charge on the molecule has to equal 0, so the oxidation number of the S must be -2.
The Potassium (K) has an oxidation number of +1. The Bromine (Br) has an oxidation number of -1.
KCLO3 the oxidation number of potassuim is +1, oxidation number of chlorine is +5 the oxidation number of oxygen is -2 and there are 3 atoms of oxygen KClO3=1+5+(-2)3=0 therefore the oxidation number of KClO3 =0 or neutral
+1 for K -2 for each O +5 for N
K has an oxidation number of +1 O has an oxidation number of (-2) x 4 So... the oxidation number for Mn is whatever is needed to make 1-8 equal to zero. Therefore, the oxidation number for Mn is +7
the oxidation number of each K is +1. But there are two K's so 1*2 is +2. the charge on the molecule has to equal 0, so the oxidation number of the S must be -2.
+1 for K and -1 for Cl
+1 for K -1 for F
+1 for K, -1 for Br
+1 for each K, -3 for N
K has an oxidation number of +1 O has an oxidation number of (-2) x 4 So... the oxidation number for Mn is whatever is needed to make 1-8 equal to zero. Therefore, the oxidation number for Mn is +7
as oxidation number of K is 1 and the molecule is neutral 1+ Cl=0 Cl= -1 Therefore, the oxidation number of Cl is -1
0 in elemental form; +1 in all its compounds