Ba2+ (aq) + SO42- (aq) → BaSO4 (s)
There is no equation in the question, only two pair of two reactants.
Complete ionic equation is:2Li^+(aq) + SO4^2-(aq) = Sr^2+(aq) + 2Cl^-(aq) ==>2Li^+(aq) + 2Cl^-(aq) + SrSO4(s)
The equation is:Ba+ + (SO4)2- = BaSO4(s)
The balanced equation for sodium sulfate (Na2SO4) plus barium chloride (BaCl2) yielding barium sulfate (BaSO4) and sodium chloride (NaCl) is: Na2SO4 + BaCl2 -> BaSO4 + 2NaCl
BaCl2+K2SO4=2KCl+BaSO4
There is no equation in the question, only two pair of two reactants.
Copper(II) sulfate has the formula CuSO4.
PbCu2
Cu2+ + (SO4)2- + Ba2+ + 2Cl- = Cu2+ + 2Cl- + BaSO4 (s)
Complete ionic equation is:2Li^+(aq) + SO4^2-(aq) = Sr^2+(aq) + 2Cl^-(aq) ==>2Li^+(aq) + 2Cl^-(aq) + SrSO4(s)
The equation is:Ba+ + (SO4)2- = BaSO4(s)
The balanced equation for sodium sulfate (Na2SO4) plus barium chloride (BaCl2) yielding barium sulfate (BaSO4) and sodium chloride (NaCl) is: Na2SO4 + BaCl2 -> BaSO4 + 2NaCl
CuSO4 + BaCl2 --> CuCl2 + BaSO4
The net ionic equation for formation of a precipitate [note correct spelling] when sodium sulfate and barium chloride solutions are mixed is Ba+2 + SO4 -2 -> BaSO4 (s)
BaCl2+K2SO4=2KCl+BaSO4
BaSO4 + 2CaCl2 --> Ba(Cl2)2 + Ca2SO4
there are no co efficents infront of any of the reactants or products