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W-V percent concentration g/mL = 1.20g/240mL = 0.005 g/mL percent
You need to add the 50ul stock solution to 1200ul of distilled water to produce 1250ul of solution with a concentration of 2ul per ml.
13.6% methanol solution.
This depends on the solution concentration.
The concentration of HCl is 11,66 g/L.
W-V percent concentration g/mL = 1.20g/240mL = 0.005 g/mL percent
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
The concentration of hcl is 0.13.
You need to add the 50ul stock solution to 1200ul of distilled water to produce 1250ul of solution with a concentration of 2ul per ml.
0.75 M
13.6% methanol solution.
.5M
The density of 40ml of saline solution in a 50 ml beaker is 1.0046g/mL. The density will vary based upon the concentration of the salt added to the solution.
0.13 is the concentration of the acetic acid solution.
It depends on the concentration of the solution. If you know the concentration(molarity) then use the equation. moles = [conc] x vol(mL) / 1000 NB The '1000' isusedto convert the concentration units of moles per litre (molL^-1) to mL.
This depends on the solution concentration.
It depends on the concentration of HCl in the solution.